Consider the quadratic function $f\left(x\right)=x^2-2x-8$f(x)=x2−2x−8.
Complete the following table of values.
$x$x | $-9$−9 | $-3$−3 | $0$0 | $5$5 | $9$9 |
$f\left(x\right)$f(x) | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ |
Hence sketch the curve.
Choose all the correct statements.
The curve is steeper at $x=6$x=6 than at $x=1$x=1.
The curve is parabolic in shape and is concave up.
At the point $f\left(n\right)$f(n), the function takes the value of $n$n.
The curve has $x$x-intercepts at $-2$−2 and $4$4.
At the point $n$n, the function takes the value of $f\left(n\right)$f(n).
As the value of $a$a is positive, the curve is concave down.
Consider the quadratic function $f\left(x\right)=-3\left(x-3\right)\left(x+1\right)$f(x)=−3(x−3)(x+1).
Consider the cubic function $f\left(x\right)=2x^3+4x^2$f(x)=2x3+4x2.
Consider the cubic function $f\left(x\right)=2x^3-2$f(x)=2x3−2.