Consider the function $f\left(x\right)=x+1$f(x)=x+1.
Graph the function on the set of axes below:
Is the function $f\left(x\right)=x+1$f(x)=x+1 a one-to-one function?
No
Yes
If a function is one-to-one, an inverse function exists. Find the inverse function $f^{-1}\left(x\right)$f−1(x), writing each line of working as an equation:
Define $y$y, the inverse of $f\left(x\right)=-4x$f(x)=−4x.
Define $y$y, the inverse of $f\left(x\right)=8x-1$f(x)=8x−1.
Consider the function $y=3x+8$y=3x+8.