NZ Level 7 (NZC) Level 2 (NCEA)
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Simplifying Exponential Expressions
Lesson

In previous chapters we've learnt to simplify expressions involving indices (or powers) using index laws, but all the powers have so far been numbers. In exponentials, we are more interested about what happens if we raise the same base to different powers, so we'll see a lot of algebraic expressions in the powers. But don't worry, the same index laws still apply! To remind ourselves they are:

Rule Recap
  • The product rule: $a^m\times a^n=a^{m+n}$am×an=am+n
  • The quotient rule: $a^m\div a^n=a^{m-n}$am÷​an=amn
  • The zero index rule:$a^0=1$a0=1
  • The power of a power rule: $\left(a^m\right)^n=a^{mn}$(am)n=amn
  • The negative index rule: $a^{-m}=\frac{1}{a^m}$am=1am
  • The fractional index rule: $a^{\frac{m}{n}}=\sqrt[n]{a^m}$amn=nam
  • The fractional base rule: $\left(\frac{a}{b}\right)^m=\frac{a^m}{b^m}$(ab)m=ambm

 

Careful!

Be careful when using these rules as the bases have to be the same! For example, if we have an expression such as $3^x\times9^x$3x×9x we can not apply any of these rules as $3\ne9$39. However if we think of $9$9 as two factors of $3$3 multiplied together we can proceed as follows:

$3^x\times9^x$3x×9x $=$= $3^x\times\left(3^2\right)^x$3x×(32)x
  $=$= $3^x\times3^{2x}$3x×32x
  $=$= $3^{x+2x}$3x+2x
  $=$= $3^{3x}$33x

Let's have a look at how to simplify (simplest index form) some more complicated examples!

 

Examples

question 1

Simplify the expression $\frac{6^{p-4q}\times36^{2q+p}}{6^{5p-3q}}$6p4q×362q+p65p3q

Think: First make sure all terms have the same base and be careful of order of operations when subtraction is concerned

Do:

$\frac{6^{p-4q}\times36^{2q+p}}{6^{5p-3q}}$6p4q×362q+p65p3q $=$= $\frac{6^{p-4q}\times\left(6^2\right)^{2q+p}}{6^{5p-3q}}$6p4q×(62)2q+p65p3q
  $=$= $\frac{6^{p-4q}\times6^{2\left(2q+p\right)}}{6^{5p-3q}}$6p4q×62(2q+p)65p3q
  $=$= $\frac{6^{p-4q}\times6^{4q+2p}}{6^{5p-3q}}$6p4q×64q+2p65p3q
  $=$= $\frac{6^{p-4q+4q+2p}}{6^{5p-3q}}$6p4q+4q+2p65p3q
  $=$= $\frac{6^{3p}}{6^{5p-3q}}$63p65p3q
  $=$= $6^{3p-\left(5p-3q\right)}$63p(5p3q)
  $=$= $6^{3p-5p+3q}$63p5p+3q
  $=$= $6^{3q-2p}$63q2p

 

question 2

If $6^x=13$6x=13, find the value of $6^{x+1}$6x+1.

question 3

Use index laws to simplify the ratio $\left(0.3\right)^a:\left(0.3\right)^{a+2}$(0.3)a:(0.3)a+2 to a ratio of whole numbers.

Outcomes

M7-6

Manipulate rational, exponential, and logarithmic algebraic expressions

91261

Apply algebraic methods in solving problems

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