3.03 Two-step equations
Determine whether the given value of x is a solution to the following equations:
x - 10 = - 1 where x = 9
x - 4 = - 5 where x = 0
x + 1 = 7 where x = 6
x - 3 = - 3 where x = 3
4 x - 2 = 18 where x = 5
6 x - 13 = 12 where x = 4
5 x + 12 = 31 where x = 4
3 x + 1 = 7 where x = 2
Solve:
-5 + x = 12
x - 4 = 10
- 5 x = 30
4 x = - 28
- 7 x = 0
- 7 x = - 28
- x = 3
2 = - x
- 10 x = - 50
\dfrac{4}{9} n = 10
\dfrac{x}{8} = 6
\dfrac{1}{8} x = - 8
- \dfrac{1}{8} x = - 8
- \dfrac{1}{8} x = 6
- 5 = \dfrac{x}{5}
- 6 = \dfrac{y}{- 7}
For each of the following equations:
Describe the operations required to solve the equation.
Now, solve the equation.
Solve:
- x - 7 = 7
- x + 5 = - 1
- 63 - 9 y = 63
7 x + 14 = 0
8 m + 9 = 65
8 x - 9 = 39
4 x - 8 = 0
5 x - 8 = 2
- 10 + 3 k = 5
4 x + 36 = 40
7 x - 63 = 49
-4x - 29 = -13
Solve:
\dfrac{x}{5} + 3 = 11
\dfrac{x}{2} - 3 = 1
\dfrac{x}{2} + 8 = 10
\dfrac{x}{7} + 3 = - 1
\dfrac{x}{8} - 17 = - 13
\dfrac{x}{8} - 13 = - 6
\dfrac{x}{6} - 3 = 4
- \dfrac{x}{9} = 4
Solve:
\dfrac{x + 9}{7} = 4
\dfrac{c - 4}{4} = 7
\dfrac{m + 11}{2} = 10
\dfrac{47 + m}{15} = 3
\dfrac{m+26}{17} = 3
\dfrac{t-5}{4} = 8
\dfrac{q-17}{3} = -4
\dfrac{m - 6}{4} = 4.25
Solve:
10 \left(p + 10\right) = 50
5 \left(t + 9\right) = 60
6 \left( x + 5 \right) = 54
3\left(n + 5\right) = 24
4 \left(k - 4\right) = 48
3 \left(s - 16\right) = - 21
9 \left(p - 3\right) = 0
2 \left(l - 12\right) = - 10
One quarter of a number is equal to triple that number less 22. Let x be the unknown number.
Write an equation in terms of x.
Find the value of x.
The product of 6 and the sum of x and 4 is equal to 42. Find the value of x.
The relationship between F degrees Fahrenheit and C degrees Celsius is F = 1.8 C + 32. Find the temperature in degrees Celsius that is equivalent to 51.8 \degree \text{F}.