Linear Equations II
Hong Kong
Stage 4 - Stage 5
Perpendicular distance
Interactive practice questions
Given a point $\left(x_1,y_1\right)$(x1,y1) and a line $Ax+By+C=0$Ax+By+C=0, what formula can we use to find the perpendicular distance $d$d between the point and the line?
$d=\frac{\left|Ax_1+By_1+C\right|}{\sqrt{A^2-B^2}}$d=|Ax1+By1+C|√A2−B2
A
$d=\frac{\left|Ax_1+By_1+C\right|}{\sqrt{A^2+B^2}}$d=|Ax1+By1+C|√A2+B2
B
$d=\frac{\left|Ax_1-By_1+C\right|}{\sqrt{A^2+B^2}}$d=|Ax1−By1+C|√A2+B2
C
$d=\frac{\left|Ax_1-By_1+C\right|}{\sqrt{A^2-B^2}}$d=|Ax1−By1+C|√A2−B2
D
Easy
< 1min
Find the perpendicular distance from the origin to the line $4x+7y+5=0$4x+7y+5=0.
Easy
3min
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