We've learnt a number of indice rules. Now we are going to look at questions that involve a combination of these rules. It's important to remember the order of operations when we're solving these questions.
A question may have any combination of indice rules. We just need to simplify it step by step, making sure we follow the order of operations.
Let's look through some examples now!
Simplify: $p^7\div p^3\times p^5$p7÷p3×p5
Think: We need to apply the index division and index multiplication laws.
Do:
$p^7\div p^3\times p^5$p7÷p3×p5 | $=$= | $p^{7-3+5}$p7−3+5 |
$=$= | $p^9$p9 |
Simplify: $\frac{\left(u^{x+3}\right)^3}{u^{x+1}}$(ux+3)3ux+1
Think: Just like in Question 2, we need to simplify the numerator using the power of a power rule, then apply the quotient rule.
Do:
$\frac{\left(u^{x+3}\right)^3}{u^{x+1}}$(ux+3)3ux+1 | $=$= | $\frac{u^{3x+9}}{u^{x+1}}$u3x+9ux+1 | Firstly, we'll simplify the numerator using the "power of a power" rule |
$=$= | $u^{3x+9-\left(x+1\right)}$u3x+9−(x+1) | Then, using the quotient rule, we can subtract the power | |
$=$= | $u^{3x+9-x-1}$u3x+9−x−1 | Expand the brackets, then simplify by collecting the like terms | |
$=$= | $u^{2x+8}$u2x+8 |
Express $\left(4^p\right)^4$(4p)4 with a prime number base in index form.
Think: We could express $4$4 as $2^2$22 which has a prime number base.
Do:
$\left(4^p\right)^4$(4p)4 | $=$= | $4^{4p}$44p |
$=$= | $\left(2^2\right)^{4p}$(22)4p | |
$=$= | $2^{8p}$28p |
Simplify $20m^6\div5m^{13}\times9m^2$20m6÷5m13×9m2, expressing your answer in positive index form.
Think: Let's express this as a fraction so the powers are on the numerator and the denominator for easy comparison.
Do:
$\frac{20m^6}{5m^{13}}\times9m^2$20m65m13×9m2 | $=$= | $\frac{4}{m^7}\times9m^2$4m7×9m2 |
$=$= | $\frac{36m^2}{m^7}$36m2m7 | |
$=$= | $\frac{36}{m^5}$36m5 |
Simplify $\frac{\left(x^2\right)^6}{\left(x^2\right)^2}$(x2)6(x2)2
Simplify $\left(u^9\times u^5\div u^{19}\right)^2$(u9×u5÷u19)2, expressing your answer in positive index form.