Solve $\sin x=\frac{\sqrt{3}}{2}$sinx=√32 for $x$x where $0^\circ\le x\le90^\circ$0°≤x≤90°.
Solve for $x$x where $0^\circ\le x\le90^\circ$0°≤x≤90°:
$2\cos x=\sqrt{3}$2cosx=√3
Solve $2\cos x-\sqrt{3}=0$2cosx−√3=0 for $x$x where $0^\circ\le x\le90^\circ$0°≤x≤90°
Find the measure of the acute angle satisfying $5\sin\theta+1=9\sin\theta$5sinθ+1=9sinθ. Give your answer correct to the nearest degree.