Given the general quadratic equation $y=ax^2+bx+c$y=ax2+bx+c, $a\ne0$a≠0, consider the following statement:
The vertex of the graph will be located at $x=\frac{b}{2a}$x=b2a.
Is the statement true?
Yes
No
What should the $x$x value of the vertex actually be?
Consider the function $y=x^2$y=x2
This is a graph of $y=x^2$y=x2.
Consider the equation $y=x^2+5$y=x2+5.