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10.02 Extension: Perpendiculars and distance

Interactive practice questions

Given a point $\left(x_1,y_1\right)$(x1,y1) and a line $Ax+By+C=0$Ax+By+C=0, what formula can we use to find the perpendicular distance $d$d between the point and the line?

$d=\frac{\left|Ax_1+By_1+C\right|}{\sqrt{A^2-B^2}}$d=|Ax1+By1+C|A2B2

A

$d=\frac{\left|Ax_1+By_1+C\right|}{\sqrt{A^2+B^2}}$d=|Ax1+By1+C|A2+B2

B

$d=\frac{\left|Ax_1-By_1+C\right|}{\sqrt{A^2+B^2}}$d=|Ax1By1+C|A2+B2

C

$d=\frac{\left|Ax_1-By_1+C\right|}{\sqrt{A^2-B^2}}$d=|Ax1By1+C|A2B2

D
Easy
< 1min

Find the perpendicular distance from the origin to the line $4x+7y+5=0$4x+7y+5=0.

Easy
3min
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