The position (in metres) of an object along a straight line after $t$t seconds is modelled by $x\left(t\right)=6t^2$x(t)=6t2.
State the velocity $v\left(t\right)$v(t) of the particle at time $t$t.
Which of the following represent the velocity of the particle after $4$4 seconds? Select all that apply.
$x'\left(4\right)$x′(4)
$v'\left(4\right)$v′(4)
$x\left(4\right)$x(4)
$v\left(4\right)$v(4)
Hence find the velocity of the particle after $4$4 seconds.
The position (in metres) of an object along a straight line after $t$t seconds is modelled by $x\left(t\right)=3t^2+5t+2$x(t)=3t2+5t+2.
We want to find the velocity of the object after $4$4 seconds.
The position (in metres) of an object along a straight line after $t$t seconds is modelled by $x\left(t\right)=3t^3-4t^2$x(t)=3t3−4t2.
The position (in metres) of an object along a straight line after $t$t seconds is modelled by $x\left(t\right)=18\sqrt{t}$x(t)=18√t.