Consider the parabola of the form $y=ax^2+bx+c$y=ax2+bx+c, where $a\ne0$a≠0
Fill in the gap to make the statement true.
The $x$x-coordinate of the vertex of the parabola occurs at $x=\editable{}$x=. The $y$y-coordinate of the vertex is found by substituting this $x$x-value into the parabola's equation and evaluating the function at this value of $x$x.
What is the line $x=\frac{-b}{2a}$x=−b2a on the parabola defined by the equation $y=ax^2+bx+c$y=ax2+bx+c ($a\ne0$a≠0)?
Consider the curve $y=x^2+6x+4$y=x2+6x+4.
Consider the function $P\left(x\right)=x^2-4x+2$P(x)=x2−4x+2.