Angles are formed by pairs of intersecting lines. If one line is rotated fully, the angle appears to be the same although numerically different. The following diagram illustrates this idea.
Angles that are related in this way are called coterminal angles.
In general, an angle coterminal with another angle differs from it by an integer multiple of $2\pi$2π or $360^{\circ}$360∘.
List some negative and positive angles that are coterminal with $115^{\circ}$115∘.
We need only add or subtract multiples of $360^{\circ}$360∘ to obtain the coterminal angles. So, we have
$...,-605^{\circ},-245^{\circ},115^{\circ},475^{\circ},835^{\circ},...$...,−605∘,−245∘,115∘,475∘,835∘,...
Find the coterminal angle closest to zero for $\frac{39\pi}{4}$39π4.
The number $\frac{39\pi}{4}$39π4 is between $9\pi$9π and $10\pi$10π. We try subtracting $5\times2\pi$5×2π. This gives $\frac{39\pi}{4}-10\pi=-\frac{\pi}{4}$39π4−10π=−π4, which is indeed the closest coterminal angle to zero.
In which quadrant does the angle $7491^{\circ}$7491∘ lie?
Here, the strategy will be to remove integer multiples of $360^{\circ}$360∘ until an angle between $0^{\circ}$0∘ and $360^{\circ}$360∘ is reached. By division, we see that $20\times360<7491<21\times360$20×360<7491<21×360. So, we subtract $20\times360^{\circ}$20×360∘ and obtain $291^{\circ}$291∘. This angle is greater than $270^{\circ}$270∘ and less than $360^{\circ}$360∘ and is therefore in the fourth quadrant.
Find the angle of smallest positive measure that is coterminal with a $489^\circ$489° angle.
Consider an angle of $-58$−58°.
Find the angle of smallest positive measure that is coterminal with $-58$−58°.
Find the angle of smallest negative measure that is coterminal with $-58$−58°.
Which quadrant does $\left(-58\right)^\circ$(−58)° lie in?
quadrant $3$3
quadrant $1$1
quadrant $4$4
quadrant $2$2
State the expression in terms of $n$n, where $n$n represents any integer, that generates all angles coterminal with $\frac{\pi}{2}$π2.
$\frac{\pi}{2}$π2$+$+$\editable{}$