Congruent triangles are triangles that are identical in shape and size. In other words, all corresponding sides and angles are equal.
We can confirm congruent shapes by seeing that if by using a combination of flips, slides or turns, we can reorient one shape to look like the other. If you have to use enlargements to stretch or change the size of the shape than they are not congruent. In this chapter, we are going to look at four different ways to prove triangles are congruent, as well as how to write these proofs.
Two triangles are considered congruent if
Normally though we can identify congruent triangles with 3 pieces of information (not the whole 6). This is because once we know 3 pieces we can use other geometrical angle rules or trigonometry side length rules to calculate the others.
If all three sides on both triangles have the same corresponding lengths then the triangles are congruent. We abbreviate this to SSS.
Writing the proof:
In $\triangle ABC$△ABC and $\triangle FGE$△FGE:
$AB$AB | $=$= | $FG$FG (given) |
$AC$AC | $=$= | $EF$EF (similarly) |
$BC$BC | $=$= | $EG$EG (similarly) |
$\therefore$∴ $\triangle ABC$△ABC | $\cong$≅ | $\triangle FGE$△FGE (SSS) |
If we know two angles and $1$1 corresponding side length, then the triangles are congruent. We abbreviate this to
Some schools and countries consider ASA and AAS as different proofs for congruency, mathematically however they are the same because if you know two angles, you can work out the third using the angle sum of a triangle is equal to $180^\circ$180°. This can change the information we have from AAS to ASA, hence they are both equivalent proofs.
If two sides and the included angle are equal on two triangles, then the triangles are congruent. We abbreviate this to SAS.
The angle used must be the one between the two sides.
Writing the proof:
In $\triangle MKP$△MKP and $\triangle AGZ$△AGZ:
$MK$MK | $=$= | $AG$AG (given) |
$KP$KP | $=$= | $ZG$ZG (similarly) |
$\angle MKP$∠MKP | $=$= | $\angle AGZ$∠AGZ (similarly) |
$\therefore$∴ $\triangle MKP$△MKP | $\cong$≅ | $\triangle AGZ$△AGZ (SAS) |
If two right-angled triangles have equal hypotenuses and a pair of corresponding sides that are equal, then these triangles are congruent. We abbreviate this to RHS.
Writing the proof:
In $\triangle ABC$△ABC and $\triangle PRQ$△PRQ:
$\angle ABC$∠ABC | $=$= | $\angle PRQ$∠PRQ $=$= $90^\circ$90° (given) |
$AC$AC | $=$= | $PQ$PQ (given) |
$AB$AB | $=$= | $PR$PR (similarly) |
$\therefore$∴ $\triangle ABC$△ABC | $\cong$≅ | $\triangle PRQ$△PRQ |
Here are the four proofs of congruency. You only need to use one of the to prove two triangles are congruent.
SSS- all sides are equal
AAS- two angles and one side are equal
SAS- two pairs of corresponding sides, and the pair of included angles are equal
RHS- right-angled triangles with equal hypotenuses and a pair of equal corresponding sides
a) Which pairs of triangles are congruent?
b) Give reasons for the congruence.
Prove that $\triangle OAB$△OAB is congruent to $\triangle OCD$△OCD where $O$O is the centre of the circle. Do this by stating three facts and then give the reason why these facts imply that the triangles are congruent.
Prove that $\triangle ABO$△ABO and $\triangle CDO$△CDO are congruent.