In the diagram, $AB=CB$AB=CB and $D$D is the midpoint of side $AC$AC.
Without using the properties of an isosceles triangle show that $\angle BAD=\angle BCD$∠BAD=∠BCD.
In $\triangle BAD$△BAD and $\triangle BCD$△BCD we have:
In the diagram , $AE$AE and $BD$BD bisect one another.
Prove that $AB\parallel ED$AB∥ED.
In the following diagram, $X$X is the centre of a circle.
By proving $\triangle XBC$△XBC is congruent to $\triangle XGF$△XGF, show that $AD\parallel EH$AD∥EH.
$ABCD$ABCD is a parallelogram with $AE=FC$AE=FC. Prove that $DE$DE=$FB$FB.