In algebra, we use letters to represent unknown values, and we call these unknowns variables or pronumerals. For example if we know that $x+2=5$x+2=5, then we can work out that $x=3$x=3 since we also know that $3+2=5$3+2=5.
Sometimes we want to do this process in reverse, however, and we substitute numbers into equations in place of variables to determine a final value. We can substitute in any kinds of numbers, including whole numbers, decimals and fractions.
Evaluate: If $x=3$x=3, evaluate $6x-4$6x−4.
Think: This means that everywhere the letter $x$x has been written, we will replace it with the number $3$3.
Do:
$6x-4$6x−4 | $=$= | $6\times3-4$6×3−4 |
$=$= | $18-4$18−4 | |
$=$= | $14$14 |
The same process applies even if there is more than one unknown value.
Evaluate: If $x=6$x=6 and $y=0.5$y=0.5, evaluate $6x-2y-12$6x−2y−12.
Think: Just like before, we will replace the letter $x$x with the number $6$6, and the letter $y$y with the number $0.5$0.5. We also need to keep the order of operations in mind when we do these kinds of calculations!
Do:
$6x-2y-12$6x−2y−12 | $=$= | $6\times6-2\times0.5-12$6×6−2×0.5−12 | replacing $x$x with $6$6, and $y$y with $0.5$0.5. |
$=$= | $36-1-12$36−1−12 | evaluating multiplication before subtraction. | |
$=$= | $23$23 |
Now let's watch some worked solutions to the following questions.
Evaluate $8x+4$8x+4 when $x=2$x=2.
For $x=10$x=10 and $y=6$y=6, evaluate $8x+6y+4$8x+6y+4