Consider $33$33 and $27$27.
What is the highest common factor of these two numbers?
Complete the gaps such that $33+27$33+27 is rewritten as an equivalent multiplication using the distributive property.
$33+27$33+27 | $=$= | $3\times\left(\editable{}+9\right)$3×(+9) |
$=$= | $\editable{}\times20$×20 |
Consider $77$77 and $143$143.
Consider the sum of $42$42 and $39$39.
Given $6\left(7+4\right)+4\left(7+4\right)$6(7+4)+4(7+4):