We know how to solve problems such as $7\times6$7×6, but what happens if we need to solve $237\times6$237×6? The area model of multiplication is a great way to see how the distributive property of multiplication works, so let's start off with this in Video 1.
Now we can use the same approach, but we don't have to draw the rectangles each time. We can break our problem into smaller problems, which is what we are doing when we use the distributive property of multiplication. After you watched Video 2, you should be okay with your $347$347 times tables!
We want to find $2\times45$2×45.
Use the area model to complete the following:
$40$40 | $5$5 | ||||||||||||
$2$2 | |||||||||||||
$2\times45$2×45 | $=$= | $2\times\left(40+5\right)$2×(40+5) |
$=$= | $2\times\editable{}+2\times5$2×+2×5 | |
$=$= | $\editable{}+\editable{}$+ | |
$=$= | $\editable{}$ |
We want to find $6\times795$6×795.
Use the area model to complete the following:
$700$700 | $90$90 | $5$5 | ||||||||||||||||
$6$6 | ||||||||||||||||||
$6\times795$6×795 | $=$= | $6\times\left(700+90+5\right)$6×(700+90+5) |
$=$= | $6\times\editable{}+6\times\editable{}+6\times\editable{}$6×+6×+6× | |
$=$= | $\editable{}+\editable{}+\editable{}$++ | |
$=$= | $\editable{}$ |
Let's use the distributive property to find $8\times153$8×153.
Using the fact that $153=100+50+3$153=100+50+3, how can we rewrite the number sentence in the form $8\times\editable{}+8\times\editable{}+8\times\editable{}$8×+8×+8×?
Fill in the blanks to solve the following:
$8\times153$8×153 | $=$= | $8\times100+8\times50+8\times3$8×100+8×50+8×3 |
$=$= | $\editable{}+\editable{}+\editable{}$++ | |
$=$= | $\editable{}$ |