Now that we know what a Discrete Random Variable (DRV) is, we want to compare this with what constitutes a Continuous Random Variable (CRV).
As you'll notice from the names, the only difference is the word Discrete which has been changed to Continuous. And that's the only difference in the definitions too!
When determining whether you're looking at a DRV or a CRV, you firstly need to make sure that the experiment or situation is random and varies.
You then need to consider whether the outcomes consist of discrete or continuous values.
Remember that what you're asking yourself is whether the outcomes are counted or measured.
The mass of each egg in an $18$18-pack carton of Extra Large Eggs ranges in weight from $67$67 g to $72$72 g.
(a) Can the weight of the eggs in the carton be modelled by a probability distribution?
Think: We need to check firstly that the outcomes (the weights of the eggs) are random and vary. We then need to think about what sort of data we're dealing with.
Do: The weights certainly vary because we're told they range between $67$67 g and $72$72 g. We know the eggs are randomly assigned to each space in the egg carton and we'd choose one at random.
We also know that we'd need to measure the weight of each egg, not count it.
Therefore we can say that this situation is modelled by a continuous random variable.
(b) Which of the following graphs best models the shape of this continuous probability distribution?
Think: Because we don't have a lot of experience with CRVs, we'll have to really think about what we expect to happen in this real-life situation. You have to use some common sense!
Do: Let's take a look at what each graph is telling us.
When we think about the weights of the eggs in a carton that is advertised as containing Extra Large Eggs, we should expect that the majority of the eggs will be the same size and weight and that there's a lower chance that an egg will be at the lower or higher range of weights. So the mean weight should have the highest probability. We are therefore looking at the fourth graph as our answer.