Recall that a logarithmic equation of the form $\log_ba=c$logba=c is equivalent to an exponential equation of the form $b^c=a$bc=a. That is, the value of the logarithm $\log_ba$logba is "the power which $b$b must be raised to in order to give $a$a".
Using this, if $a$a is a rational power of $b$b then we can simplify the logarithm nicely. For example,
$\log_28=\log_2\left(2^3\right)=3$log28=log2(23)=3.
In any other case, where $a$a is not a rational power of $b$b, we can use a calculator (or other technology) to approximate the value. In particular, we can use the logarithm property
$\log_ba=\frac{\log_na}{\log_nb}$logba=lognalognb
to rewrite any logarithm using a base that is available on the calculator. For example,
$\log_213=\frac{\log_{10}13}{\log_{10}2}\approx3.7004$log213=log1013log102≈3.7004.
Here is a graph of the function $y=\log_2x$y=log2x:
From the graph, we can see a few features:
The function is increasing, but at a decreasing rate.
In fact, these features are true for any function of the form $y=\log_bx$y=logbx, where $b>1$b>1.
As with other functions that we've looked at, we can transform the graphs of logarithms in a few ways:
Note that in all of these cases, the asymptote of the function is still along the $y$y-axis. Additionally, a function of the form $y=a\log_bx$y=alogbx still intercepts the $x$x-axis at the point $\left(1,0\right)$(1,0).
To sketch the graph of a function of the form $y=a\log_bx+k$y=alogbx+k, start by identifying the locations of the asymptote and the $x$x-intercept.
Then plot a couple of extra points to see the general shape of the graph.
Consider the function $y=3\log_2x$y=3log2x.
Solve for the $x$x-coordinate of the $x$x-intercept.
Complete the table of values for $y=3\log_2x$y=3log2x.
$x$x | $\frac{1}{2}$12 | $1$1 | $2$2 | $4$4 |
---|---|---|---|---|
$y$y | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ |
State the equation of the vertical asymptote.
Sketch the graph of $y=3\log_2x$y=3log2x.
Consider the function $y=\log_3x-1$y=log3x−1.
Solve for the $x$x-coordinate of the $x$x-intercept.
Complete the table of values for $y=\log_3x-1$y=log3x−1.
$x$x | $\frac{1}{3}$13 | $1$1 | $3$3 | $9$9 |
---|---|---|---|---|
$y$y | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ |
State the equation of the vertical asymptote.
Sketch the graph of $y=\log_3x-1$y=log3x−1.
Consider the function $y=3\log_4\left(-x\right)$y=3log4(−x).
Solve for the $x$x-coordinate of the $x$x-intercept.
Complete the table of values for $y=3\log_4\left(-x\right)$y=3log4(−x).
$x$x | $-16$−16 | $-4$−4 | $-1$−1 | $-\frac{1}{4}$−14 |
---|---|---|---|---|
$y$y | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ |
State the equation of the vertical asymptote.
Sketch the graph of $y=3\log_4\left(-x\right)$y=3log4(−x).