So what you will have found is that the $m$m value affects the slope.
If $m<0$m<0, the slope is negative and the line is decreasing
if $m>0$m>0, the slope is positive and the line is increasing
if $m=0$m=0 the slope is $0$0 and the line is horizontal
Also, the larger the value of $m$m the steeper the line
Y-Intercept
We also found that the $b$b value affects the $y$y intercept.
If $b$b is positive then the line is vertically translated (moved) up.
If $b$b is negative then the line is vertically translated (moved) down.
Transformations of the Line
So from equations in this form, $y=mx+b$y=mx+b, we instantly have enough information to understand what this line looks like and to describe the transformations from the basic line $y=x$y=x.
Examples
By first identifying the slope and $y$y intercept, describe the transformations of the following lines from the basic line $y=x$y=x.
Question 1
$y=3x$y=3x
slope is $3$3
$y$y intercept is $0$0
Transformations of change: The line $y=x$y=x is made steeper due to a slope of $3$3 and is not vertically translated (it has the same $y$y-intercept as $y=x$y=x).
Question 2
$y=-2x$y=−2x
slope is $-2$−2
$y$y intercept is $0$0
Transformations of change: The line $y=x$y=x is made steeper due to a slope of $2$2, is reflected on the $x$x-axis (due to a negative slope), and is not vertically translated.
Question 3
$y=\frac{x}{2}-3$y=x2−3
slope is $\frac{1}{2}$12
$y$y intercept is $-3$−3
Transformations of change: the line $y=x$y=x is made less steep due to a slope of $\frac{1}{2}$12 and is vertically translated $3$3 units down (a $y$y-intercept of $-3$−3 compared to a $y$y-intercept of $0$0 in $y=x$y=x).
Question 4
$2y=-4x+10$2y=−4x+10
First we need to rewrite it in the slope intercept form.
$y=-2x+5$y=−2x+5
slope is $-2$−2
$y$y intercept is $5$5
Transformations of change: the line $y=x$y=x is made more steep due to a slope of $2$2, and is reflected on the $x$x-axis (due to a negative slope). It is vertically translated $5$5 units up.
Creating equations from information given about the line
To create an equation of the form $y=mx+b$y=mx+b, we need 2 pieces of information: if we know the slope and the $y$y-intercept, we can instantly write down the equation.
Example
What is the equations of the line with the a slope of $\frac{3}{4}$34 and a $y$y intercept of $-2$−2?
The equation of the line will be:
$y=mx+b$y=mx+b
$y=\frac{3}{4}x-2$y=34x−2
Here are some worked examples.
Question 1
It is easier to read the slope and $y$y-intercept from a linear equation if you rearrange the equation into slope-intercept form:
$y=mx+b$y=mx+b
What is the slope of the line $y=\frac{3-2x}{8}$y=3−2x8?
Question 2
Given that the line $y=mx+c$y=mx+c has a slope of $-2$−2 and passes through $\left(-6,-3\right)$(−6,−3):
Find $c$c, the value of the $y$y-intercept of the line.
Find the equation of the line in the form $y=mx+c$y=mx+c.
Outcomes
10P.LR2.02
Identify, through investigation, y = mx + b as a common form for the equation of a straight line, and identify the special cases x = a, y = b;