Applications of Standard Deviation using sample population
Interactive practice questions
The mean of a set of scores is $77$77 and
the standard deviation is $29$29. Find the value of:
$\text{Mean }-\text{Standard Deviation}$Mean −Standard Deviation
$\text{Mean }+2\times\text{Standard Deviation}$Mean +2×Standard Deviation
$\text{Mean }-\frac{\left(2\times\text{Standard Deviation}\right)}{3}$Mean −(2×Standard Deviation)3
$\text{Mean }+\frac{\left(4\times\text{Standard Deviation}\right)}{5}$Mean +(4×Standard Deviation)5
$\text{Mean }+3\times\text{Standard Deviation}$Mean +3×Standard Deviation
$\text{Mean }-2\times\text{Standard Deviation}$Mean −2×Standard Deviation
The mean of a set of scores, denoted by $\mu$μ, is $51$51 and
the standard deviation is $16$16, and is denoted by $\sigma$σ. Find the value of:
The literacy rate of a population is used to help measure the level of development of a country. The average literacy rate in a particular country is $59%$59%, and the standard deviation is $5%$5%. The literacy rate varies from place to place within the country.
The following table shows the marks obtained by a student in two subjects.