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VCE 11 General 2023

11.05 Trigonometry of obtuse angles

Lesson

Types of angles

Remember the following classifications of angles:

  • An acute angle has an angle measure between 0\degree and 90\degree

  • An obtuse angle has an angle measure between 90\degree and 180\degree

  • A reflex angle has an angle measure between 180\degree and 360\degree

Examples

Example 1

Is this angle acute, obtuse, or reflex?

An acute angle
Worked Solution
Create a strategy

Check the degree of rotation of the angle.

Apply the idea

The given angle is an acute angle as it measures less than 90\degree and forms a narrow, small angle.

Example 2

Is this angle acute, obtuse, or reflex?

An obtuse angle
Worked Solution
Create a strategy

Check the degree of rotation of the angle.

Apply the idea

The given angle is an obtuse angle as it measures between 90\degree and 180\degree, and forms a wide, large angle.

Idea summary

Remember the following classifications of angles:

  • An acute angle has an angle measure between 0\degree and 90\degree

  • An obtuse angle has an angle measure between 90\degree and 180\degree

  • A reflex angle has an angle measure between 180\degree and 360\degree

Unit circle

Trigonometry is not limited to right-angled triangles, which by definition always have one right-angle and two acute angles. In fact, trigonometric ratios can be defined for an angle of any magnitude, including obtuse and reflex angles. This concept can be visualised using the unit circle.

A right angled triangle with an angle theta, sides of x and y, and a hypotenuse of 1.

Consider a right-angled triangle with a hypotenuse of length 1 unit, with no other known measurements:

The two smaller, unknown side-lengths defined by x and y can be calculated: \cos\theta =\dfrac{x}{1} \qquad \sin \theta=\dfrac{y}{1}

Since dividing any number by 1 gives a same number answer, x=\cos \theta and y=\sin\theta.

Now consider a Cartesian plane that has a circle drawn with a radius of 1, centred at the origin (0,\,0):

A Cartesian plane showing the 4 quadrants and unit circle with an acute angle inside. Ask your teacher for more information.

This is known as the unit circle, because it is a circle with a radius of 1 unit. Notice how this same right-angled triangle from before now appears inside the unit circle in quadrant 1 (where x and y are both positive), and the hypotenuse of the triangle is now the radius of the circle. So for any angle \theta between 0\degree and 90\degree, the corresponding x and y coordinates on the circle can be found by evaluating trigonometric ratios \cos\theta and \sin\theta to create the coordinate pair \left(\cos\theta,\,\sin\theta\right).

The angle \theta inside the unit circle is always measured starting from the positive x-axis. So what happens when this angle is extended beyond 90\degree?

A Cartesian plane showing the 4 quadrants and unit circle with an obtuse angle inside. Ask your teacher for more information.

The point on the unit circle is now in quadrant 2. Angles are still measured from the positive x-axis, so in the 2nd quadrant, angles have measures between 90\degree and 180\degree, hence they are obtuse angles. Remember that x values on the cartesian plane are negative when looking to the left of the origin (centre) and positive to the right of the origin. So in this 2nd quadrant, x values are negative and y values are positive.

So because x=\cos \theta and y=\sin \theta, that means the cosine of an obtuse angle must be a negative trigonometric ratio. And the sine of an obtuse angle is a positive trigonometric ratio.

The unit circle can be used to find the trigonometric ratio of a reflex angle, angles greater than 360\degree, and negative angles too. But in this course, only acute and obtuse angles will be used when solving trigonometry problems.

The unit circle can also be used to evaluate tangent ratios for any positive (or negative) angles. But in this course, only sine and cosine ratios will be evaluated for angles between 90\degree and 180\degree.

Examples

Example 3

The graph shows an angle a in standard position with its terminal side intersecting the circle at P\left(-\dfrac{24}{25},\,\dfrac{7}{25}\right).

-1
1
x
-1
1
y
a

Find the value of \sin a.

Worked Solution
Create a strategy

\sin a is equal to the y-coordinate of the given point.

Apply the idea

\sin a=\dfrac{7}{25}

b

Find the value of \cos a.

Worked Solution
Create a strategy

\cos a is equal to the x-coordinate of the given point.

Apply the idea

\cos a=-\dfrac{24}{25}

Idea summary
A Cartesian plane showing the 4 quadrants and unit circle with an acute angle inside. Ask your teacher for more information.

This is known as the unit circle, because it is a circle with a radius of 1 unit. Notice how this same right-angled triangle from before now appears inside the unit circle in quadrant 1 (where x and y are both positive), and the hypotenuse of the triangle is now the radius of the circle. So for any angle \theta between 0\degree and 90\degree, the corresponding x and y coordinates on the circle can be found by evaluating trigonometric ratios \cos\theta and \sin\theta to create the coordinate pair \left(\cos\theta,\,\sin\theta\right).

Sine and cosine ratios of obtuse angles

A scientific calculator can evaluate the sine, cosine or tangent of any angle of any magnitude. For example, entering \sin 120\degree in the calculator will generate an answer of 0.8660, correct to 4 decimal places. However, the unit circle can also be used to evaluate trigonometric ratios of obtuse angles, in terms of corresponding acute angles.

Consider an obtuse angle theta. Remember that this angle corresponds to a coordinate pair on the unit circle that is in the 2nd quadrant.

Semicircle showing the first and second quadrants with obtuse angle theta. Ask your teacher for more information.

The y-coordinate of this point in the 2nd quadrant is identical to the y-coordinate of this other point in the 1st quadrant with supplementary acute angle \alpha. Since y=\sin \theta, this means that for this obtuse angle, \sin \theta = \sin\alpha. Because \theta + \alpha = 180\degree (definition of supplementary angles), the following relationship exists for the sine of all obtuse angles: \sin \theta =\sin \left(180\degree -\theta \right)

The x-coordinate of this point in the 2nd quadrant is identical to the x-coordinate of this other point in the 1st quadrant with supplementary acute angle \alpha. Since x=\cos \theta, this means that for this obtuse angle, \cos \theta = -\cos\alpha. Because \theta + \alpha = 180\degree, the following relationship exists for the sine of all obtuse angles: \cos \theta =-\cos \left(180\degree -\theta \right)

Examples

Example 4

Evaluate \cos 126\degree correct to two decimal places and make note of the sign of your answer.

Worked Solution
Create a strategy

Determine in which quadrant the angle lies and the sign of the ratio.

Apply the idea
This image shows the signs of the trigonometric ratios in each quadrant. Ask your teacher for more information.

Starting at the positive x-axis and rotating 126\degree anticlockwise, we move into the second quadrant.

This diagram shows cosine is negative in the second quadrant and we know that \cos \theta\degree=-\cos\left(180\degree - \theta\degree\right).

\displaystyle \cos 126\degree \displaystyle =\displaystyle -\cos (180\degree -126\degree) Substitute the angle
\displaystyle =\displaystyle -\cos 54\degree Evaluate the angle
\displaystyle =\displaystyle -0.59 Simplify
Reflect and check

The sign of any trigonometric ratio can be determined from its quadrant, using the mnemonic "All Stations To Central" or ASTC.

Example 5

Write the following trigonometric ratio using an acute angle: \sin 147\degree

Worked Solution
Create a strategy

Determine in which quadrant the angle lies and the sign of the ratio.

Apply the idea
This image shows the signs of the trigonometric ratios in each quadrant. Ask your teacher for more information.

147\degree is between 90\degree and 180\degree so it is in the second quadrant.

This diagram shows sine is positive in the second quadrant and we know that \sin \theta\degree=+\sin\left(180\degree - \theta\degree\right).

\displaystyle \sin 147\degree \displaystyle =\displaystyle -\sin (180\degree -147\degree) Substitute the angle
\displaystyle =\displaystyle -\sin 33\degree Evaluate the angle

Example 6

Consider the unit semi-circle diagram shown below.

Semicircle with reference angle of 60 degrees shows coordinates of point A. Ask your teacher for more information.
a

State the values of \sin 60\degree and \cos 60\degree, to four decimal places where appropriate.

Worked Solution
Create a strategy

Use your calculator and make sure it is in degrees mode.

Apply the idea

Using a calculator we get: \sin 60\degree=0.866 \qquad \qquad \cos 60\degree=0.5

b

Using point A and the symmetry of the unit circle, state the coordinates of point B.

Worked Solution
Create a strategy

Use the fact that points A and B are symmetrical with respect to the y-axis.

Apply the idea

Points A and B have same coordinate but different signs in x-coordinate (A in 1st quadrant, B in 2nd). So, B: \, (-0.5,\,0.866)

c

Determine the values of \sin 120\degree and \cos 120\degree, to four decimal places where appropriate.

Worked Solution
Create a strategy

Use your calculator and make sure it is in degrees mode.

Apply the idea

Using a calculator we get: \sin 120\degree=0.866 \qquad \qquad \cos 120\degree=-0.5

Reflect and check

Notice that the values are same in the part (a) due to the formulas, \sin \theta=\sin \left(180\degree-\theta \right) and \cos \theta=-\cos \left(180\degree-\theta \right). These formulas state that the sine and cosine of an angle \theta are equal to the sine and cosine of its supplementary angle \left(180\degree-\theta \right), respectively, with a sign change for cosine.

Idea summary
A diagram showing equivalent angles for each quadrant using trigonometric ratios. Ask your teacher for more information.

Now that we can determine the sign of a ratio based on its quadrant, we can use the symmetry of the circle to find equivalent angles - angles with the same trigonometric ratio, up to their sign.

The reference angle is always between 0\degree and 90\degree.

Possible angles of sine and cosine ratios

When working with right-angled triangles, unknown angles are found by finding the inverse sine, cosine or tangent of a given ratio of a triangle's side lengths. This is the case for angles between 0\degree and 90\degree.

From the unit circle work completed above, it was discovered that the cosine of acute angles produce positive ratios, whilst the cosine of obtuse angles produce negative ratios. So when trying to find angles between 0\degree and 180\degree, the angle will be either acute or obtuse depending on whether the given ratio is positive or negative.

When it comes to sine ratios, the results are ambiguous, because the sine of any angle between 0\degree and 180\degree will always produce a positive ratio. So without any known point on a unit circle, if an angle could be either acute or obtuse, then a positive sine ratio creates two possible angle solutions.

Consider any position on the unit circle, (x,\,y) can be found using angle \theta: x=\cos \theta \qquad\qquad y=\sin \theta

The following identities can be used to find sine & cosine ratios for obtuse angles \sin \theta =\sin \left(180\degree -\theta \right) \qquad\qquad \cos \theta =-\cos \left(180\degree -\theta \right)

Examples

Example 7

Determine the solution(s) to the equation \sin \theta=0.65, for 0\degree \leq \theta \leq 180\degree. If there is more than one solution, write all answers on the same line separated by commas. Round your answer(s) to the nearest degree.

Worked Solution
Create a strategy

Use your calculator and make sure it is in degrees mode.

Apply the idea
\displaystyle \sin \theta\displaystyle =\displaystyle 0.65Write the equation
\displaystyle \theta\displaystyle =\displaystyle \sin ^{-1}(0.65)Apply the inverse sine to both sides
\displaystyle =\displaystyle 41\degreeEvaluate using your calculator

Using the relationship from before, \sin\theta=\sin\left(180\degree-\theta\right), this means that \sin 41\degree=\sin\left(180\degree-41\degree\right)=\sin 139\degree. Therefore \theta has two possible solutions, \theta=41\degree ,\,139\degree

Example 8

Determine the solution(s) to the equation \cos \theta =-0.22, for 0\degree \leq \theta \leq 180\degree. If there is more than one solution, write all answers on the same line separated by commas. Round your answer(s) to the nearest degree.

Worked Solution
Create a strategy

Use your calculator and make sure it is in degrees mode.

Apply the idea
\displaystyle \cos \theta\displaystyle =\displaystyle -0.22Write the equation
\displaystyle \theta\displaystyle =\displaystyle \cos ^{-1}(-0.22)Apply the inverse cosine to both sides
\displaystyle =\displaystyle 103\degreeEvaluate using your calculator

Since the above ratio is negative, there will only be the one obtuse angle solution to consider between 0\degree and 180\degree. Therefore \theta has one possible solution, \theta=103\degree

Idea summary

Consider any position on the unit circle, (x,\,y) can be found using angle \theta: x=\cos \theta \qquad\qquad y=\sin \theta

The following identities can be used to find sine & cosine ratios for obtuse angles \sin \theta =\sin \left(180\degree -\theta \right) \qquad\qquad \cos \theta =-\cos \left(180\degree -\theta \right)

Outcomes

U2.AoS4.3

the definition of sine and cosine for angles up to 180°

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