When we solve a system of equation using the addition method, what happens when the system has no solutions?
When we add the equations, all the variables are eliminated and we end up with a false statement such as $0=2$0=2.
When we add the equations, we end up with a statement such as $x=2$x=2.
When we add the equations, all the variables are eliminated and we end up with a true statement such as $2=2$2=2.
Consider the following system of equations.
$-8x$−8x | $-$− | $y$y | $=$= | $0$0 |
$-5x$−5x | $+$+ | $3y$3y | $=$= | $6$6 |
We are solving this system using the elimination method.
Use the elimination method by adding both equations to solve for $y$y and then for $x$x.
Equation 1 | $8x+3y=-11$8x+3y=−11 |
Equation 2 | $-8x-5y=29$−8x−5y=29 |
Use the elimination method by subtraction to solve for $x$x and then $y$y.
Equation 1 | $2x-5y=1$2x−5y=1 |
Equation 2 | $-3x-5y=-39$−3x−5y=−39 |