Interactive practice questions
Kerry currently pays $\$50$$50 a month for her internet service. She is planning to switch to a fibre optic cable service.
Write an equation for the total cost $T$T of Kerry's current internet service over a period of $n$n months.
For the fibre optic cable service, Kerry pays a one-off amount of $\$1200$$1200 for the installation costs and then a monthly fee of $\$25$$25. Write an equation of the total cost $T$T of Kerry's new internet service over $n$n months.
Fill in the table of values for the total cost of the current internet service, given by $T=50n$T=50n
| $n$n | $1$1 | $6$6 | $12$12 | $18$18 | $24$24 |
|---|---|---|---|---|---|
| $T$T (dollars) | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ |
Fill in the table of values for the total cost of the fibre optic cable service, given by $T=25n+1200$T=25n+1200
| $n$n | $1$1 | $6$6 | $12$12 | $18$18 | $24$24 |
|---|---|---|---|---|---|
| $T$T (dollars) | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ | $\editable{}$ |
Choose the correct pair of lines that show the total cost of Kerry's current internet service and the total cost of her new internet service.
Using the graph from the previous question, determine how many months it will take for Kerry to break even on her new internet service.
A line $L_1$L1 is perpendicular to $y=9x+7$y=9x+7 and passes through the point of intersection of the lines $y=3x-7$y=3x−7 and $9x-4y-10=0$9x−4y−10=0.
Consider the system of linear equations
| $-3x-12y$−3x−12y | $=$= | $6$6 |
| $-2x-4y$−2x−4y | $=$= | $-4$−4 |
Consider the system of linear equations
| $4x+4y$4x+4y | $=$= | $6$6 |
| $5x+3y$5x+3y | $=$= | $3$3 |