Consider the equation $-6\sin^{-1}x=\pi$−6sin−1x=π.
Solve the equation for $\sin^{-1}x$sin−1x.
Consider your answer from part a. Does the equation have a solution?
Not enough information
Yes
No
Solve $\sin^{-1}x=-\frac{\pi}{6}$sin−1x=−π6 for $x$x.
Consider the equation $4\tan^{-1}x=-3\pi$4tan−1x=−3π.
Consider the equation $5\cos^{-1}\left(\frac{x}{3}-\frac{\pi}{3}\right)=5\pi$5cos−1(x3−π3)=5π.
Consider the equation $\sin^{-1}x-\tan^{-1}1=-\frac{\pi}{4}$sin−1x−tan−11=−π4.