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AustraliaVIC
VCE 12 General 2023

1.08 The 68-95-99.7% rule

Interactive practice questions

The mean of a set of scores is $77$77 and

the standard deviation is $29$29. Find the value of:

a

$\text{Mean }-\text{Standard Deviation}$Mean Standard Deviation

b

$\text{Mean }+2\times\text{Standard Deviation}$Mean +2×Standard Deviation

c

$\text{Mean }-\frac{\left(2\times\text{Standard Deviation}\right)}{3}$Mean (2×Standard Deviation)3

d

$\text{Mean }+\frac{\left(4\times\text{Standard Deviation}\right)}{5}$Mean +(4×Standard Deviation)5

e

$\text{Mean }+3\times\text{Standard Deviation}$Mean +3×Standard Deviation

f

$\text{Mean }-2\times\text{Standard Deviation}$Mean 2×Standard Deviation

Easy
3min

The following figure shows the approximate percentage of scores lying within various standard deviations from the mean of a normal distribution. The heights of $600$600 boys are found to approximately follow such a distribution, with a mean height of $145$145 cm and a standard deviation of $20$20 cm. Find the number of boys with heights between:

Medium
4min

Complete the following statements for a normal distribution using the empirical rule.

Easy
1min

In a normal distribution, what percentage of scores lie between the mean and $1$1 standard deviation above the mean? Use the empirical rule to find your answer.

Easy
< 1min
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Outcomes

U3.AoS1.6

the normal model and the 68–95–99.7% rule, and standardised values (𝑧-scores)

U3.AoS1.18

solve problems using 𝑧-scores and the 68–95–99.7% rule

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