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3.05 Dividing of 3 and 4 digit numbers

Lesson

Are you ready?

Do you remember the different methods for dividing two or three digit numbers by single digit numbers? Let's try this problem to practice.

Find the value of $369\div3$369÷​3.

Learn

This video looks at using partitioning to divide large numbers by breaking them up into parts that are easier to divide.

Vocabulary:

Another word that we can use to describe the ones place is 'units'.

Apply

Question 1

We're going to break $9372$9372 into $6000+3000+360+12$6000+3000+360+12 to calculate $9372\div6$9372÷​6.

Follow these steps.

  1. Calculate $6000\div6$6000÷​6.

  2. Calculate $3000\div6$3000÷​6.

  3. Calculate $360\div6$360÷​6.

  4. Calculate $12\div6$12÷​6.

  5. Using the fact that $9372=6000+3000+360+12$9372=6000+3000+360+12, calculate $9372\div6$9372÷​6.

Learn

This video looks at how we can use partitioning when the number we are dividing cannot be divided evenly by the divisor.

Apply

Question 2

Calculate $647\div2$647÷​2 by doing the following.

  1. Calculate $600\div2$600÷​2.

  2. Calculate $40\div2$40÷​2.

  3. Calculate $6\div2$6÷​2.

  4. Using the fact that $647=600+40+6+1$647=600+40+6+1, fill in the boxes with the missing numbers.

    $2$2 goes into six hundred forty seven $\editable{}$ times with a remainder of $\editable{}$

Learn

This video reminds us how to use the division algorithm. We can use the same process for division with and without a remainder.

Apply

Question 3

Find the value of $2516$2516$\div$÷​$8$8.

  1. $2516$2516$\div$÷​$8$8$=$=$\editable{}$ remainder $\editable{}$.

 

Remember!

As our number gets larger, we need to work through more steps in our division, but the process is still the same. If we can't share into equal groups, we end up with a remainder.

Outcomes

MA.5.NSO.2.2

Divide multi-digit whole numbers, up to five digits by two digits, including using a standard algorithm with procedural fluency. Represent remainders as fractions.

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