7.02 Distances in the plane using the Pythagorean theorem
Consider point P plotted on the coordinate plane:
If the coordinates of P is at \left( - 15 , 8\right), find the distance of P from the origin.
The points P\left( - 3 , - 2 \right), Q\left( - 3 , - 4 \right) and R\left(1, - 4 \right) are the vertices of a right triangle, as shown on the coordinate plane:
Find the length of the following segments, correct to three decimal places where necessary:
\overline{PQ}
\overline{QR}
\overline{PR}
Consider the following triangle on the coordinate plane:
Use the Pythagorean theorem to find the exact length of \overline{AC}.
Consider \overline{AB} that has been graphed on the coordinate plane:
Find the vertical component of the distance from A to B.
Find the horizontal component of the distance from A to B.
Use the Pythagorean theorem to find the exact length of \overline{AB}.
Consider \overline{AB} that has been graphed on the coordinate plane:
Find the vertical component of the distance from A to B.
Find the horizontal component of the distance from A to B.
Use the Pythagorean theorem to find the exact length of \overline{AB}.
Consider \overline{AB} that has been graphed on the coordinate plane:
Find the exact length of \overline{AB}.
Find the length of \overline{AB} shown on the graph. Round your answer to two decimal places.
Find the exact distance from A \left(-1, - \dfrac{3}{5} \right) to B \left(4, \dfrac{12}{5}\right).
Consider the segment joining points P\left(16, - 10 \right) and Q\left(4, 6\right):
Find the length of \overline{PQ}.
Point N is the midpoint of \overline{PQ}. Find the distance from P to N.
Which point is farther from P \left(5, - 1 \right): M \left(10, - 6 \right) or N \left(1, 2\right)?