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8.01 Right triangles and the Pythagorean theorem

Lesson

Concept summary

An angle has a different name based on its measure.

  • An acute angle is an angle larger than 0 \degree and smaller than 90 \degree
  • A right angle is an angle measuring exactly 90 \degree
  • An obtuse angle is an angle larger than 90 \degree and smaller than 180 \degree

A right triangle is a triangle containing an interior right angle.

The Pythagorean theorem and its converse describe how the side lengths of right triangles are related.

Pythagorean theorem

If a triangle is a right triangle, then the square of the length of the hypotenuse is equal to the sum of the squares of its legs lengths.

For the given triangle, a^2+b^2=c^2

Right triangle uppercase A uppercase C uppercase B with right angle uppercase C. Uppercase A uppercase B has a length of lowercase c, uppercase A uppercase C has a length of lowercase b, and uppercase B uppercase C has a length of lowercase a.
\displaystyle a^2+b^2=c^2
\bm{a}
is the length of one of the legs (shorter sides) of the right triangle
\bm{b}
is the length of the other leg of the right triangle
\bm{c}
is the length of the hypotenuse of the right triangle
Converse of Pythagorean theorem

If the lengths a, b and c of the three sides of a triangle satisfy the relationship a^2+b^2=c^2, then the triangle is a right triangle.

Pythagorean triple

A set of three non-zero whole numbers a, b, and c such that a^2+b^2=c^2

Example:

3, 4, and 5

Worked examples

Example 1

Find the value of c in the triangle below.

A right triangle with legs of length 14 and 48, and a hypotenuse of length c.

Approach

The triangle is a right triangle so the hypotenuse, c, can be found using the Pythagorean theorem.

Solution

\displaystyle a^2+b^2\displaystyle =\displaystyle c^2Pythagorean theorem
\displaystyle 14^2+48^2\displaystyle =\displaystyle c^2Substitution
\displaystyle 196+2304\displaystyle =\displaystyle c^2Simplify
\displaystyle 2500\displaystyle =\displaystyle c^2Combine like terms
\displaystyle 50\displaystyle =\displaystyle cSquare root both sides
\displaystyle c\displaystyle =\displaystyle 50Symmetric property of equality

We have found that c=50.

Reflection

We can use the Pythagorean theorem to solve for missing leg lengths as well.

Notice that in this example, 2500 is a perfect square so our answer for c is an integer. This means \left\{ 14, 48, 50\right\} is a Pythagorean triple.

Example 2

Use the Pythagorean theorem to determine whether the triangle below is a right triangle.

A triangle with side lengths of 9, 16, and 18.

Approach

We want to use the converse of the Pythagorean theorem to determine if the triangle is a right triangle.

Let a and b represent the two shorter side lengths. The hypotenuse will be c.

Once we have labeled the sides, we want to find the value of a^2+b^2 and the value of c^2.

If a^2+b^2=c^2 then the triangle is a right triangle by the converse of the Pythagorean theorem.

If a^2+b^2 \neq c^2 then the triangle is not a right triangle for the same reason.

Solution

Let a=9, b=16, and c=18. Now we can calculate the following:

\displaystyle a^2+b^2\displaystyle =\displaystyle 9^2+16^2
\displaystyle {}\displaystyle =\displaystyle 337

And

\displaystyle c^2\displaystyle =\displaystyle 18^2
\displaystyle {}\displaystyle =\displaystyle 324

This is not a right triangle because 337 \neq 324 so a^2+b^2 \neq c^2

Example 3

The size of a computer monitor is often given as the length of its diagonal. Rowena has just bought a 19 inch monitor, meaning that the display has a diagonal length of 19 inches. The screen has a 4:3 width-to-height ratio (aspect ratio).

Determine the width and height of Rowena's new monitor.

Approach

We know the length of the diagonal of the monitor is 19 inches. We also know that the lengths of the width and height are in a ratio of 4:3, but we don't know the exact length of either the width or height.

We can use this information by letting the width be 4x inches and the height be 3x inches, and draw a diagram as follows:

A diagram of a rectangular computer monitor with a width of 4 x, height of 3 x, and diagonal length of 19 inches.

Solution

From the diagram we have drawn, we can use the Pythagorean theorem to find x, and then determine the dimensions of the monitor from there:

\displaystyle \left(4x\right)^2 + \left(3x\right)^2\displaystyle =\displaystyle 19^2Apply Pythagorean theorem
\displaystyle 16x^2 + 9x^2\displaystyle =\displaystyle 361Evaluate powers
\displaystyle 25x^2\displaystyle =\displaystyle 361Combine like terms
\displaystyle x^2\displaystyle =\displaystyle \frac{361}{25}Divide both sides by 25
\displaystyle x\displaystyle =\displaystyle \frac{19}{5}Take the square root of both sides

So we have that x = \dfrac{19}{5} = 3.8 inches. We can now use this to determine the width and height of the monitor:

  • \text{Width}\, = 4x = 4\left(3.8\right) = 15.2\, \text{in}
  • \text{Height}\, = 3x = 3\left(3.8\right) = 11.4\, \text{in}

Outcomes

G.N.Q.A.1

Use units as a way to understand real-world problems.*

G.N.Q.A.1.A

Use appropriate quantities in formulas, converting units as necessary.

G.SRT.C.5

Solve triangles.*

G.SRT.C.5.A

Know and use the Pythagorean Theorem and trigonometric ratios (sine, cosine, tangent, and their inverses) to solve right triangles in a real-world context.

G.MP1

Make sense of problems and persevere in solving them.

G.MP2

Reason abstractly and quantitatively.

G.MP3

Construct viable arguments and critique the reasoning of others.

G.MP4

Model with mathematics.

G.MP5

Use appropriate tools strategically.

G.MP6

Attend to precision.

G.MP7

Look for and make use of structure.

G.MP8

Look for and express regularity in repeated reasoning.

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