7.06 Solving trigonometric equations 1

Interactive practice questions

Find the measure in degrees of the acute angle satisfying $\sin\theta=\frac{1}{\sqrt{2}}$sinθ=1√2.

Easy

1min

Find the measure of the angle satisfying $\cos\theta=\frac{1}{\sqrt{2}}$cosθ=1√2 for $0^\circ<\theta<90^\circ$0°<θ<90°.

Easy

< 1min

Find the measure in degrees of the acute angle satisfying $\tan\theta=\sqrt{3}$tanθ=√3.

Easy

< 1min

Use the relationships sin^2 A + cos^2 A = 1, sec^2 A = 1 + tan^2 A, cosec^2 A = 1 + cot^2 A, sinA/cosA = tan A and cosA/sinA = cotA.