iGCSE (2021 Edition)

# 1.06 Irrational numbers

Lesson

## What is an irrational number?

A rational number is a number which can be written as a fraction where both the numerator and denominator are integers. An irrational number is a number which cannot be written as a fraction of two integers.

We can write any terminating or recurring decimal as a fraction, therefore these are rational numbers. However, decimals which are neither terminating nor recurring are irrational numbers.

Rational and irrational numbers
• rational number is a number which can be written as a fraction where both the numerator and denominator are integers.
• An irrational number is a number which cannot be written as a fraction of two integers.
• A surd is a root which is irrational.
• A number has an exact value. In the case of fractions and roots, the exact value must be a fraction or root.
• Numbers also have approximations. These are numbers which are close but not equal to the exact value. We usually find approximations by rounding the exact value. For example, if $\frac{2}{3}$23 is the exact value, then $0.667$0.667 is an approximation.

#### Worked examples

##### Example 1

Use a calculator to try and work out if the following numbers are rational or irrational. If they're rational, express them in fractional form.

Are the following numbers rational or irrational? $\sqrt{6}$6, $-0.0047$0.0047, $-\sqrt[3]{27}$327 and $\frac{9}{2}$92

Think We want to identify whether these numbers can be expressed as fractions, terminating decimals, recurring decimals, integers, or surds.

Do:

• $6$6 is not a square number, so $\sqrt{6}$6 looks like it will be a surd, and if we evaluate it with our calculator we get:

$\sqrt{6}=2.44948974$6=2.44948974$\ldots$

This does not simplify to a rational number, so it is irrational.

• $-0.0047$0.0047 is a terminating decimal so it can be expressed as a fraction as follows:
 $-0.0047$−0.0047 $=$= $\frac{-0.0047}{1}$−0.00471​ $=$= $\frac{-47}{10000}$−4710000​

This is a fraction so it is rational.

• $27$27 is a perfect cube, so the cube root of $27$27 will be an integer:

$-\sqrt[3]{27}=-3$327=3

This simplifies down to an integer so it is rational.

• $\frac{9}{2}$92 is already a fraction, so this is rational.

## Simplifying surds

The square root function reverses the squaring function. Similarly, the cube root function undoes the cubing function.

In algebraic notation, we can write this as $\sqrt{A^2}=A$A2=A and $\sqrt[3]{B^3}=B$3B3=B. It is also true that $\left(\sqrt{A}\right)^2=A$(A)2=A and $\left(\sqrt[3]{B}\right)^3=B$(3B)3=B.

Square root and cube root expressions can sometimes be written in simpler forms using these facts, together with the other familiar surd rules.

We can use these ideas to simplify expressions like $\sqrt{16}$16 and $\sqrt{121}$121, where the numbers in the surd are perfect squares, or expressions like $\sqrt[3]{27}$327 and $\sqrt[3]{125}$3125, where the numbers in the surd are perfect cubes.

If we have a number like $\sqrt{7}$7 or $\sqrt{29}$29, we cannot simplify this any more than it already is, as the number in the surd is a prime number, but what if the number in the surd contains a factor that is a perfect square or perfect cube?

For example, an expression like $\sqrt{32}=\sqrt{16\times2}$32=16×2. Can we still simplify these types of expressions?

#### Exploration

One method to check whether an expression can be simplified is by looking at its prime factors. For example, given the expression $\sqrt{18}$18, we first look at the prime factors of $18$18 which gives us $3\times3\times2=3^2\times2$3×3×2=32×2.

Now we can write $\sqrt{18}$18 as $\sqrt{3^2\times2}=\sqrt{3^2}\times\sqrt{2}$32×2=32×2. In this step we have used the important fact that $\sqrt{A\times B}=\sqrt{A}\times\sqrt{B}$A×B=A×B.

The first term in the product $\sqrt{3^2}\times\sqrt{2}$32×2 is of the form $\sqrt{A^2}=A$A2=A, so the fully simplified expression becomes $3\sqrt{2}$32.

From this example we can see that if any factor appears two times within a square root, or three times within a cube root, then the expression can be further simplified. This is equivalent to looking for a factor that is a perfect square for square root expressions, or a perfect cube for cube root expressions.

Did you know?

Any positive real number has two square roots, one positive and one negative, but the square root function $\sqrt{x}$x only gives the positive square root.

This mean that the square root function and the square function are technically not inverses if we consider all real numbers. They are if we only consider the non-negative numbers.

#### Worked examples

##### Example 2

Simplify $\sqrt{8}$8.

Think: If we can find any factors of $8$8 that are perfect squares, then we can simplify the expression using the fact that $\sqrt{a^2b}=a\sqrt{b}$a2b=ab.

Do: The factors of $8$8 are $1$1, $2$2, $4$4, and $8$8. Let's use the perfect square $4$4 to rewrite the expression and simplify.

 $\sqrt{8}$√8 $=$= $\sqrt{4\times2}$√4×2 Replace $8$8 with two factors $=$= $\sqrt{4}\times\sqrt{2}$√4×√2 Use the fact that $\sqrt{A\times B}=\sqrt{A}\times\sqrt{B}$√A×B=√A×√B $=$= $\sqrt{2^2}\times\sqrt{2}$√22×√2 Rewrite $4$4 as $2^2$22 $=$= $2\sqrt{2}$2√2 Use the fact that $\sqrt{A^2}=A$√A2=A

##### Example 3

Simplify $\sqrt{392}$392.

Think: Looking at the prime factors gives us $392=2^3\times7^2$392=23×72. Notice that we can write $2^3$23 as $2\times2^2$2×22.

Do: After we substitute $392$392 with its prime factors we can use the rules of manipulation of surds to simplify the expression.

 $\sqrt{392}$√392 $=$= $\sqrt{2\times2^2\times7^2}$√2×22×72 $=$= $2\times7\times\sqrt{2}$2×7×√2 $=$= $14\sqrt{2}$14√2

Rules for manipulation of surds

Here are some key identities that we will find useful to simplify expressions involving surds.

$\sqrt{a^2}=a$a2=a

$\sqrt{a\times b}=\sqrt{a}\times\sqrt{b}$a×b=a×b

And from these two we can see that:

$\sqrt{a^2b}=a\sqrt{b}$a2b=ab.

#### Practice questions

##### Question 1

Is $\sqrt[3]{47}$347 rational or irrational?

1. Rational

A

Irrational

B

Rational

A

Irrational

B

##### question 2

Simplify $\sqrt{180}$180.

##### Question 3

Simplify $\frac{1}{2}\sqrt[3]{8\times6}$1238×6.

### Outcomes

#### 0606C4.1B

Perform simple operations with surds.