Consider the diagram.
Why is $BE$BE parallel to $CD$CD?
$\angle ABE$∠ABE and $\angle ACD$∠ACD form a pair of equal corresponding angles.
$\angle ABE$∠ABE and $\angle ACD$∠ACD form a pair of supplementary cointerior angles.
$\angle ABE$∠ABE and $\angle ACD$∠ACD form a pair of equal alternate angles.
Which angle is equal to $\angle BEA$∠BEA?
$\angle BEA=\editable{}$∠BEA=
How do we know that $\triangle ABE\sim\triangle ACD$△ABE~△ACD?
Two right-angled triangles have the ratio of their hypotenuses equal to the ratio of another pair of matching sides
Two pairs of matching sides are in the same ratio and the included angles are equal
All pairs of matching sides are in the same ratio
All three pairs of corresponding angles are equal.
What is the scale factor relating $\triangle ABE$△ABE to $\triangle ACD$△ACD?
Solve for the value of $f$f.
Consider $\triangle ABC$△ABC and $\triangle PQR$△PQR.
Consider the following diagram:
In the diagram, $QR\parallel ST$QR∥ST.