From the time of the ancient Babylonians, it has been the practice to divide circles into $360$360 small arcs. An angle can be subtended by extending two lines (rays) from points on the circumference and connecting them at the centre of the circle. The angle subtended at the centre by any one of those $360$360 small arcs, is called one degree. In effect, an arc of the circle is used as a measure of the angle it subtends.
In a similar way, it's possible to define the angle subtended by an arc at the centre of a circle, by the ratio of the arc length divided by the radius. Angles defined this way are called radians and an angle in radians can be calculated as $\theta=\frac{s}{r}$θ=sr, where $s$s is the arc length and $r$r is the radius of the circle. Hence, the angle subtended by an arc whose length is equal to the radius is $1$1 radian. Radians are an alternate way to describe angles and are the international standard unit for measuring angles. Since angles in radian measure are in essence just fractions of the circle, they do not require a unit, although some writers indicate that radian measure is being used by adding a superscript c after a number or the abbreviation rad, like this: $2^c$2c or $2$2$rad$rad. (The c is short for circular-measure.)
Restricting attention to circles of radius one unit, $1$1 radian would be the angle subtended by an arc of length $1$1 unit.
Recall that the circumference of a circle is found using the formula $C=2\pi r$C=2πr. So, if the radius ($r$r) is $1$1, then the circumference is $2\pi$2π.
The angle represented by a full turn around the circle is $2\pi$2π radians. This is equivalent to $360^\circ$360°.
A half-circle makes an angle of $\pi$π radians or $180^\circ$180° and a right-angle is $\frac{\pi}{2}$π2 radians.
Since:
$\pi^c$πc | $=$= | $180^\circ$180° |
$1^c$1c | $=$= | $\frac{180}{\pi}^\circ$180π° |
$\approx$≈ | $57.3^\circ$57.3° |
In practice, angles given in radian measure are commonly expressed as fractions of $\pi$π.
Since $\pi^c=180^\circ$πc=180°, to change from degrees to radians divide by $180^\circ$180° and multiply by $\pi$π and vice versa to convert the other way.
Convert $\frac{8\pi}{6}$8π6 to degrees.
$\frac{8\pi}{6}^c$8π6c | $=$= | $\frac{8\pi}{6}\times\frac{180^\circ}{\pi}$8π6×180°π |
$=$= | $\frac{1440\pi}{6\pi}^\circ$1440π6π° | |
$=$= | $240^\circ$240° |
Just as the trigonometric functions were explored for angles measured in degrees in the last lesson, these functions can also be applied to angles measured using radians.
Let's look at the sign and symmetry of the trigonometric functions in terms of radians.
Express $\cos\frac{13\pi}{20}$cos13π20 in terms of a first quadrant angle.
The angle $\frac{13\pi}{20}$13π20 is between $\frac{\pi}{2}$π2 and $\pi$π, so it is in the second quadrant. The point representing $\frac{13\pi}{20}$13π20 on the unit circle diagram, where the radius cuts the circle, must have a negative horizontal coordinate. Therefore, $\cos\frac{13\pi}{20}$cos13π20 must be the same as $-\cos\left(\pi-\frac{13\pi}{20}\right)=-\cos\frac{7\pi}{20}$−cos(π−13π20)=−cos7π20.
A point $P$P on the unit circle is at at angle of $\frac{4\pi}{3}$4π3 from the positive $x$x-axis, find the coordinates of point $P$P.
The coordinates will be in the form $\left(\cos\theta,\sin\theta\right)$(cosθ,sinθ), so let's use our calculator to evaluate each.
$\cos(\theta)$cos(θ) | $=$= | $\cos\left(\frac{4\pi}{3}\right)$cos(4π3) |
$=$= | $-\frac{1}{2}$−12 |
$\sin(\theta)$sin(θ) | $=$= | $\sin\left(\frac{4\pi}{3}\right)$sin(4π3) |
$=$= | $-\frac{\sqrt{3}}{2}$−√32 |
Hence, $P$P is located at $\left(-\frac{1}{2},-\frac{\sqrt{3}}{2}\right)$(−12,−√32). We can see that both coordinates are negative since the angle $\frac{4\pi}{3}$4π3 places point $P$P in the third quadrant.
Given that $x=\pi$x=πc represents half a circle, what fraction of the circumference of the unit circle does $x=\frac{\pi}{4}$x=π4c represent?
Convert $-300^\circ$−300° to radians.
Give your answer in exact form.
Convert $\frac{2\pi}{3}$2π3 radians to degrees.
Consider the expression $\tan\frac{4\pi}{3}$tan4π3.
In which quadrant is $\frac{4\pi}{3}$4π3?
first quadrant
third quadrant
second quadrant
negative quadrant
What positive acute angle is $\frac{4\pi}{3}$4π3 related to?
Is $\tan\frac{4\pi}{3}$tan4π3 positive or negative?
positive
negative
Rewrite $\tan\frac{4\pi}{3}$tan4π3 in terms of its relative acute angle. You do not need to evaluate $\tan\frac{4\pi}{3}$tan4π3.