5.05 Solving trigonometric equations 1

Find the measure of the angle satisfying $\cos\theta=\frac{1}{\sqrt{2}}$cosθ=1√2​ for $0^\circ<\theta<90^\circ$0°<θ<90°.

Find the measure in degrees of the acute angle satisfying $\tan\theta=\sqrt{3}$tanθ=√3.