Now that we have worked with finding the surface area of rectangular prisms, we can work to find the surface area of cylinders.
Using the applet below, see how we can unfold a cylinder. Consider the following questions.
Notice that when the curved surface is unfolded, it becomes a rectangle. By rotating the circle on top of the rectangle, can you see how the circumference of the circle is equal to the length of the rectangular piece?
From this applet we can see that:
This means that we can break down the total surface area of a cylinder in the following way:
S.A. of a Cylinder | $=$= | Area of $2$2 circles + Area of $1$1 rectangle |
From net |
$=$= | $2\times\pi r^2+lw$2×πr2+lw |
Using our known formulas |
|
$=$= | $2\pi r^2+\left(2\pi r\right)\times w$2πr2+(2πr)×w |
The length of the rectangle is the circumference of the circle |
|
$=$= | $2\pi r^2+2\pi rh$2πr2+2πrh |
The width of the rectangle is the height of the cylinder |
$\text{Surface Area of a Cylinder }=2\pi r^2+2\pi rh$Surface Area of a Cylinder =2πr2+2πrh
Consider the following cylinder with a height of $35$35 cm and base radius of $10$10 cm. Find the surface area of the cylinder.
Round your answer to two decimal places.
Find the surface area of the cylinder shown.
Give your answer to the nearest two decimal places.
A cylindrical can of radius $7$7 cm and height $10$10 cm is open at one end. What is the external surface area of the can correct to two decimal places?