A base form of an exponential function is $y=a^x$y=ax for $a>0$a>0 and $a\ne1$a≠1 and the variable $x$x is in the exponent. These graphs take the following form:
How did the graph of $y=\left(\frac{1}{2}\right)^x$y=(12)x compare to that of $y=2^x$y=2x? Can you see they are a reflection of each other across the $y$y-axis? In general, for $a>0$a>0 the graph of $g\left(x\right)=\left(\frac{1}{a}\right)^x$g(x)=(1a)x is equivalent to $g\left(x\right)=a^{-x}$g(x)=a−x, which is a decreasing exponential function and a reflection of the graph $f\left(x\right)=a^x$f(x)=ax across the $y$y-axis.
Let's look at the graphs of $f\left(x\right)=a^x$f(x)=ax and $y=A\times a^{b\left(x-h\right)}+k$y=A×ab(x−h)+k and the impact the parameters have on the key features. Use the applet below to observe the impact of $A$A, $b$b, $h$h and $k$k for a particular $a$a value:
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To obtain the graph of $y=A\times a^{b\left(x-h\right)}+k$y=A×ab(x−h)+k from the graph of $y=a^x$y=ax:
We can see in particular, the vertical translation by $k$k units causes the horizontal asymptote to become $y=k$y=k.
Consider the function $y=\left(\frac{1}{2}\right)^x$y=(12)x
Which two functions are equivalent to $y=\left(\frac{1}{2}\right)^x$y=(12)x ?
$y=\frac{1}{2^x}$y=12x
$y=2^{-x}$y=2−x
$y=-2^x$y=−2x
$y=-2^{-x}$y=−2−x
Sketch a graph of $y=2^x$y=2x on the coordinate plane.
Using the result of the first part, sketch $y=\left(\frac{1}{2}\right)^x$y=(12)x on the same coordinate plane.
Consider the function $y=8^{-x}+6$y=8−x+6.
What value is $8^{-x}$8−x always greater than?
$0$0
$1$1
$8$8
Hence what value is $8^{-x}+6$8−x+6 always greater than?
$6$6
$14$14
$8$8
Hence how many $x$x-intercepts does $y=8^{-x}+6$y=8−x+6 have?
State the equation of the asymptote of the curve $y=8^{-x}+6$y=8−x+6.
What is the domain of the function?
$x<0$x<0
$x>0$x>0
$x>6$x>6
all real $x$x
What is the range of the function?
Beginning with the equation $y=6^x$y=6x, fill in the gaps to find the equation of the new function that results from the given transformations.
The function is dilated by a factor of $5$5 vertically. We get the equation:
$\editable{}$
The new function is then translated $3$3 unit up. The resulting equation is: $\editable{}$
What is the horizontal asymptote of the new function?
What is the $y$y-intercept of the new function?
Using the previous parts, pick the correct graph for $y=5\times6^x+3$y=5×6x+3.
The graph represents an exponential function that has the form $y=a^x+k$y=ax+k.
State the equation for the horizontal asymptote.
State the equation of the function.
The graph represents an exponential function that has the form $y=a^{x-h}+k$y=ax−h+k.
State the value of $k$k for this function.
Determine the value of $h$h for this function.
State the equation for the exponential function.