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Stage 5.1-3

2.01 Irrational numbers

Lesson

Rational and irrational numbers

A rational number is a number which can be written as a fraction where both the numerator and denominator are integers. An irrational number is a number which cannot be written as a fraction of two integers.

We can write any terminating or recurring decimal as a fraction, therefore these are rational numbers. However, decimals which are neither terminating nor recurring are irrational numbers.

A surd is a root which is irrational.

A number has an exact value. In the case of fractions and roots, the exact value must be a fraction or root.

Numbers also have approximations. These are numbers which are close but not equal to the exact value. We usually find approximations by rounding the exact value. For example, if \dfrac{2}{3} is the exact value, then 0.667 is an approximation.

Examples

Example 1

Is \sqrt[3]{47} rational or irrational?

Worked Solution
Create a strategy

Put the number in your calculator.

Apply the idea

When \sqrt[3]{47} we get 3.608826080139. It looks like it goes on forever with no pattern, so it is irrational.

Also 47 is not a cube number, in other words there is no interger cubed that gives 47 since 3^3=27 and 4^3=64. So this further confirms that \sqrt[3]{47} is irrational.

Idea summary

A rational number is a number which can be written as a fraction where both the numerator and denominator are integers.

An irrational number is a number which cannot be written as a fraction of two integers.

A surd is a root which is irrational.

A number has an exact value. In the case of fractions and roots, the exact value must be a fraction or root.

Numbers also have approximations. These are numbers which are close but not equal to the exact value. We usually find approximations by rounding the exact value. For example, if \dfrac{2}{3} is the exact value, then 0.667 is an approximation.

Simplify surds

The square root function reverses the squaring function. Similarly, the cube root function undoes the cubing function.

In algebraic notation, we can write this as \sqrt{A^{2}}=A and \sqrt[3]{B^{3}}=B. It is also true that \left( \sqrt{A} \right)^{2}=A and \left( \sqrt[3]{B} \right)^{3}=B.

Square root and cube root expressions can sometimes be written in simpler forms using these facts, together with the other familiar surd rules.

We can use these ideas to simplify expressions like \sqrt{16} and \sqrt{121}, where the numbers in the surd are perfect squares, or expressions like \sqrt[3]{27} and \sqrt[3]{125}, where the numbers in the surd are perfect cubes.

If we have a number like \sqrt{7} or \sqrt{29}, we cannot simplify this any more than it already is, as the number in the surd is a prime number, but what if the number in the surd contains a factor that is a perfect square or perfect cube?

One method to check whether an expression can be simplified is by looking at its prime factors. For example, given the expression \sqrt{18}, we first look at the prime factors of 18 which gives us 3 \times 3 \times 2 = 3^{2} \times 2.

Now we can write \sqrt{18} as \sqrt{3^{2}} \times \sqrt{2}. In this step we have used the important fact that \sqrt{A \times B}=\sqrt{A} \times \sqrt{B}.

The first term in the product \sqrt{3^{2}} \times \sqrt{2} is of the form \sqrt{A^{2}}=A, so the fully simplified expression becomes 3\sqrt{2}.

From this example we can see that if any factor appears two times within a square root, or three times within a cube root, then the expression can be further simplified. This is equivalent to looking for a factor that is a perfect square for square root expressions, or a perfect cube for cube root expressions.

Any positive real number has two square roots, one positive and one negative, but the square root function \sqrt{x} only gives the positive square root.

This mean that the square root function and the square function are technically not inverses if we consider all real numbers. They are if we only consider the non-negative numbers.

Here are some key identities that we will find useful to simplify expressions involving surds.

\sqrt{a^{2}}=a

\sqrt{a \times b}=\sqrt{a}\times \sqrt{b}

And from these two we can see that: \begin{aligned} \sqrt{a^{2} b}&= \sqrt{a^{2}} \times \sqrt{b}\\ &=a\sqrt{b} \end{aligned}

Examples

Example 2

Simplify \sqrt{12}.

Worked Solution
Create a strategy

Find the highest perfect square that is a factor.

Apply the idea

We can find that 12 = 4 \times 3 where 4 is a perfect square.

\displaystyle \sqrt{12}\displaystyle =\displaystyle \sqrt{4} \times \sqrt{3}Write the surd as a product of its factors
\displaystyle =\displaystyle 2\times \sqrt{3}Evaluate \sqrt{4}
\displaystyle =\displaystyle 2 \sqrt{3}Simplify

Example 3

Simplify \dfrac{1}{2} \sqrt[3]{8 \times 6}.

Worked Solution
Create a strategy

Use \sqrt[3]{A \times B} =\sqrt[3]{A} \times \sqrt[3]{B} to split up \sqrt[3]{8 \times 6} into 2 factors.

Apply the idea
\displaystyle \dfrac{1}{2}\sqrt[3]{8 \times 6}\displaystyle =\displaystyle \dfrac{1}{2} \times \sqrt[3]{8} \times \sqrt[3]{6}Write the surd as a product of its factors
\displaystyle =\displaystyle \dfrac{1}{2} \times \sqrt[3]{2^{3}} \times \sqrt[3]{6}Rewrite 8 as 2^{3}
\displaystyle =\displaystyle \dfrac{1}{2} \times 2 \times \sqrt[3]{6}Simplify \sqrt[3]{2^{3}} as 2
\displaystyle =\displaystyle \sqrt[3]{6}Simplify
Idea summary

Identities that that are useful when simplifying expressions involving surds:

\sqrt{a^{2}}=a

\sqrt[3]{a^{3}}=a

\sqrt{a \times b}=\sqrt{a}\times \sqrt{b}

\sqrt{a^{2} b}=a\sqrt{b}

Outcomes

MA5.3-6NA

performs operations with surds and indices

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