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5.01 The midpoint of a segment

Interactive practice questions

To find the midpoint of an interval we want to find the mean of the two $x$x-coordinates and the mean of the two $y$y-coordinates.

Which of the following formulae correctly describes the coordinates of the midpoint of the points $\left(x_1,y_1\right)$(x1,y1) and $\left(x_2,y_2\right)$(x2,y2)?

$\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)$(x1+x22,y1+y22)

A

$\left(\frac{x_1-x_2}{2},\frac{y_1-y_2}{2}\right)$(x1x22,y1y22)

B

$\left(x_1+x_2,y_1+y_2\right)$(x1+x2,y1+y2)

C

$\left(\frac{x_1+y_1}{2},\frac{x_2+y_2}{2}\right)$(x1+y12,x2+y22)

D
Easy
< 1min

$M$M is the midpoint of $A$A $\left(5,-6\right)$(5,6) and $B$B $\left(5,2\right)$(5,2).

Easy
< 1min

$M$M is the midpoint of Point $A$A $\left(6,5\right)$(6,5) and Point $B$B $\left(14,7\right)$(14,7).

Easy
< 1min

$M$M is the midpoint of $A$A $\left(5,4\right)$(5,4) and $B$B $\left(5,10\right)$(5,10).

Easy
< 1min
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Outcomes

VCMNA308

Find the distance between two points located on a Cartesian plane using a range of strategies, including graphing software.

VCMNA309

Find the midpoint and gradient of a line segment (interval) on the Cartesian plane using a range of strategies, including graphing software.

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