$\$3900$$3900 is invested for three years at a rate of $10%$10% per annum, compounding annually.
Complete the recurrence relation for this situation.
$t_{n+1}$tn+1$=$=$\editable{}$$t_n$tn, where $t_0$t0$=$=$\editable{}$.
Use the sequence facility of your calculator to complete the table below to determine the final value of the investment.
Balance + interest | Total balance | Interest earned | |
---|---|---|---|
First year | $-$− | $\$3900$$3900 | $\$390$$390 |
Second year | $\$3900+\$390$$3900+$390 | $\$4290$$4290 | $\$429$$429 |
Third year | $\$4290+\$$$4290+$$\editable{}$ | $\$$$$\editable{}$ | $\$$$$\editable{}$ |
Fourth year | $\$4719$$4719$+$+$\$$$$\editable{}$ | $\$$$$\editable{}$ | $-$− |
Calculate the total interest earned over the three years.
$\$8000$$8000 is invested at $6%$6% p.a., compounded annually.
Callum invests $\$5700$$5700 into an investment account that pays $3.2%$3.2% per annum, compounded annually.
Erica invests $\$50000$$50000 into an investment account that pays $2.8%$2.8% per annum, compounded annually.