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1.10 Solve cubic equations

Lesson

Similar to solving quadratics we have a few methods to choose between when solving cubic equations:

  • Solve using algebraic manipulation - For cubics such as $2x^3+16=0$2x3+16=0.
  • Factorise - Fully factorising the cubic we can then use the null factor law to solve. If $a\times b\times c=0$a×b×c=0 then either $a=0$a=0 or $b=0$b=0 or $c=0$c=0.
  • Technology - Once we have extracted the important information from a question and formed an equation, we could use our calculator to solve the equation graphically or algebraically. 

 

When factorising a cubic recall we can factorise by:

  • using the highest common factor
  • factor special forms such as the sum and difference of cubes
  • identifying a single factor, then using division to establish the remaining quadratic. From here you would employ any of the factorising methods for quadratics.  

 

Practice questions

Question 1

Solve the equation $x^3=-8$x3=8.

QUESTION 2

Solve the equation $\left(x+8\right)\left(x+4\right)\left(1+x\right)=0$(x+8)(x+4)(1+x)=0.

  1. State the solutions on the same line, separated by commas.

QUESTION 3

Solve the equation $x^3-49x=0$x349x=0.

  1. State the solutions on the same line, separated by a comma.

QUESTION 4

The cubic $P\left(x\right)=x^3-2x^2-5x+6$P(x)=x32x25x+6 has a factor of $x-3$x3.

  1. Solve for the roots of the cubic. If there is more than one root, state the solutions on the same line separated by commas.

QUESTION 5

Use technology to solve the cubic equation $48x^3-212x^2+84x+209=-36$48x3212x2+84x+209=36.

  1. If there is more than one root, state the solutions on the same line separated by commas.

Outcomes

1.1.20

solve cubic equations using technology, and algebraically in cases where a linear factor is easily obtained

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