Consider the equation $2x^2-7=0$2x2−7=0.
Are $\frac{\sqrt{7}}{2}$√72 and $-\frac{\sqrt{7}}{2}$−√72 the solutions of the equation?
There is not enough information to determine if $\frac{\sqrt{7}}{2}$√72 and $-\frac{\sqrt{7}}{2}$−√72 are solutions of the equation.
No, $\frac{\sqrt{7}}{2}$√72 and $-\frac{\sqrt{7}}{2}$−√72 are not solutions of the equation.
$\frac{\sqrt{7}}{2}$√72 and $-\frac{\sqrt{7}}{2}$−√72 are only some of the solutions of the equation.
Yes, $\frac{\sqrt{7}}{2}$√72 and $-\frac{\sqrt{7}}{2}$−√72 are the only solutions of the equation.
Which of the following are the solutions of the equation? Select the two correct options.
$x=\pm\sqrt{\frac{7}{2}}$x=±√72
$x=\pm\frac{\sqrt{14}}{7}$x=±√147
$x=\pm\frac{\sqrt{14}}{2}$x=±√142
$x=\pm\sqrt{\frac{2}{7}}$x=±√27
Solve $x^2+6x-55=0$x2+6x−55=0 for $x$x.
Consider the equation $x\left(x+9\right)=-20$x(x+9)=−20.
Solve for the unknown, leaving your answer in exact form.
$8-7m-m^2=-2m^2+m+2$8−7m−m2=−2m2+m+2