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9.05 Solving two-step equations

Interactive practice questions

Consider the equation $3p+6=21$3p+6=21.

a

If we want to make $p$p the subject of the equation, what is the first step we should take?

Divide both sides by $3$3 to find the value of $p+6$p+6.

A

Subtract $6$6 from only the left-hand side of the equation.

B

Divide only the left-hand side of the equation by $3$3.

C

Subtract $6$6 from both sides to find the value of $3p$3p.

D
b

What is the second step we should take to make $p$p the subject?

Divide both sides by $3$3 to find the value of $p$p.

A

Add $6$6 to only the left-hand side of the equation.

B

Add $6$6 to both sides to find the value of $3p+6$3p+6.

C

Divide only the left-hand side of the equation by $3$3.

D
c

Apply the steps found in parts (a) and (b) to find the solution to the equation.

Enter each line of working as an equation.

Easy
1min

Consider the equation $\frac{y}{8}+3=5$y8+3=5.

Easy
1min

Consider the equation $5\left(n-7\right)=35$5(n7)=35.

Easy
2min

Consider the equation $10\left(p+10\right)=120$10(p+10)=120.

Easy
1min
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MA4-10NA

uses algebraic techniques to solve simple linear and quadratic equations

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