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9.01 Areas of special quadrilaterals

Interactive practice questions

If this parallelogram is cut along the dotted line, the pieces can be rearranged to form a rectangle:

A parallelogram with a width of 9 cm and a vertical height of 6 cm as indicated by a dashed line. This dashed line cuts the parallelogram into two shapes. A right trapezoid (colored brown) with a longer base on top and a shorter base on the bottom, and a right-angled triangle (colored green). The green right-angled triangle is from the left side of the parallelogram and the right trapezoid is the remaining shape. The green right-angled triangle is flipped horizontally and repositioned to the right side of the right trapezoid to form a rectangle. This rectangle has a longer width labeled 9 cm and a height of 6 cm.
a

Complete the table to find the area of the rectangle.

$\text{Area of rectangle }$Area of rectangle $=$= $\text{length }\times\text{width }$length ×width cm2
$A$A $=$= $\editable{}\times\editable{}$× cm2 (Fill in the values for the length and width)
$A$A $=$= $\editable{}$ cm2 (Complete the multiplication to find the area)
b

Now find the area of the parallelogram.

Easy
1min

A rhombus has diagonals measuring $8$8 m by $14$14 m. It can be divided into two triangles as shown below.

Easy
2min

Consider the rhombus shown on the left:

Easy
1min

Consider the trapezium shown below which has been split into a rectangle and a right-angled triangle.

Easy
2min
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Outcomes

MA4-12MG

calculates the perimeters of plane shapes and the circumferences of circles

MA4-13MG

uses formulas to calculate the areas of quadrilaterals and circles, and converts between units of area

MA4-17MG

classifies, describes and uses the properties of triangles and quadrilaterals, and determines congruent triangles to find unknown side lengths and angles

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