Quadratic Equations

Hong Kong

Stage 4 - Stage 5

An object launched from the ground has a height (in feet) after $t$`t` seconds that is modelled by the graph.

Loading Graph...

a

What is the maximum height of the object?

$576$576 feet

A

$6$6 feet

B

$24$24 feet

C

$600$600 feet

D

b

After how many seconds is the object at its maximum height?

$13$13 seconds

A

$4$4 seconds

B

$8$8 seconds

C

$6$6 seconds

D

c

How many seconds after launch does the object return to the ground?

$0$0 seconds

A

$6$6 seconds

B

$13$13 seconds

C

$12$12 seconds

D

Easy

Less than a minute

On Earth, the equation $d=4.9t^2$`d`=4.9`t`2 is used to find the distance (in metres) an object has fallen after $t$`t` seconds. (Assuming no air resistance or buoyancy)

The distance a freely falling object falls is modelled by the formula $d=16t^2$`d`=16`t`2, where $d$`d` is the distance in feet that the object falls and $t$`t` is the time elapsed in seconds.

On the moon, the equation $d=0.8t^2$`d`=0.8`t`2 is used to approximate the distance an object has fallen after $t$`t` seconds. (Assuming no air resistance or buoyancy). On Earth, the equation is $d=4.9t^2$`d`=4.9`t`2.

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