Trigonometry

Hong Kong

Stage 1 - Stage 3

Find the measure in degrees of the acute angle satisfying $\sin\theta=\frac{1}{\sqrt{2}}$`s``i``n``θ`=1√2.

Easy

Approx a minute

Find the measure of the angle satisfying $\cos\theta=\frac{1}{\sqrt{2}}$`c``o``s``θ`=1√2 for $0^\circ<\theta<90^\circ$0°<`θ`<90°.

Find the measure in degrees of the acute angle satisfying $\tan\theta=\sqrt{3}$`t``a``n``θ`=√3.

Find the measure in degrees of the acute angle satisfying $5\sqrt{2}\sin\theta-5=0$5√2`s``i``n``θ`−5=0.

Sign up to access Practice Questions

Get full access to our content with a Mathspace account