The applet below contains a triangle with several special segments drawn. Move the vertex of the triangle around and click the checkboxes to show and hide each special segment type. Let's think about the answers to the following questions.
No matter where we move the points of the triangle, the altitude is always a segment that is perpendicular to the base and passes through the vertex.
An altitude of a triangle is a segment from any vertex and perpendicular to the line containing the opposite side.
By its definition, the altitude does not need to be inside the triangle. It might even coincide with one of the sides of the triangle.
No matter where we move the points in the applet, the median is always inside the triangle. The median is the segment that connects one of the vertices of the triangle to the midpoint of the opposite side.
A median of a triangle is a segment whose endpoints are a vertex of the triangle and the midpoint of the opposite side.
Recall that an angle bisector is a ray from the vertex of the angle that divides an angle into two congruent angles. This definition holds for the angle bisectors of a triangle. By this definition, an angle bisector will always pass through the vertex of a triangle.
We can see in the applet above that the perpendicular bisector of a triangle always intersects the midpoint of a side. It's also always at a right angle to it. That's what makes it the perpendicular bisector. However, we can also see that it doesn't always intersect the vertex of the opposite side.
If we move the vertex of the triangle in the applet so that the triangle is isosceles, a special situation occurs. All the special segments overlap!
We can prove that this is true for any isosceles triangle using what we know about congruent triangles and their corresponding parts.
In the triangle shown below, what does the dashed line represent?
An angle bisector
A perpendicular bisector
An altitude
A median
In the triangle shown below, what does the dashed line represent?
An angle bisector.
A perpendicular bisector.
An altitude.
A median.
Given $\overline{MQ}$MQ is an altitude to isosceles triangle $MRP$MRP, prove that $\overline{MQ}$MQ is also an angle bisector.