3. Functions

Utah Math 2 - 2020 Edition

3.08 Review: Exponential growth and decay

Lesson

Certain growth and decay situations arise that naturally lead to the formulation of a rule that can be used generally.

An amount of $$5000$5000 is invested at $6$6% per year until it triples in value. When will that be?

**Think:** Increasing an amount A by $6$6% is equivalent to applying the factor $1.06$1.06, simply because $A\left(1.06\right)=A\left(1+0.06\right)=A+\frac{6}{100}A$`A`(1.06)=`A`(1+0.06)=`A`+6100`A`.

The amount $6$6% is referred to the rate of growth of the investment.

**Do:** In our problem, the factor must be applied each successive year as illustrated in this table:

Year | Amount | Pattern |
---|---|---|

$0$0 | $5000$5000 | $5000$5000 |

$1$1 | $5000\left(1.06\right)$5000(1.06) | $5000\left(1.06\right)^1$5000(1.06)1 |

$2$2 | $5000\left(1.06\right)\left(1.06\right)$5000(1.06)(1.06) | $5000\left(1.06\right)^2$5000(1.06)2 |

$3$3 | $5000\left(1.06\right)\left(1.06\right)\left(1.06\right)$5000(1.06)(1.06)(1.06) | $5000\left(1.06\right)^3$5000(1.06)3 |

$4$4 | $5000\left(1.06\right)\left(1.06\right)\left(1.06\right)\left(1.06\right)$5000(1.06)(1.06)(1.06)(1.06) | $5000\left(1.06\right)^4$5000(1.06)4 |

There is a pattern to the table. After $n$`n` years the principal amount of $5000 will have the future value given by $A_n=5000\left(1.06\right)^n$`A``n`=5000(1.06)`n`.

The future value will be triple the principal when $A_n=5000\left(1.06\right)^n>15000$`A``n`=5000(1.06)`n`>15000. We can solve this using logarithms:

$5000\left(1.06\right)^n$5000(1.06)n |
$>$> | $15000$15000 |

$\left(1.06\right)^n$(1.06)n |
$>$> | $3$3 |

$n\log1.06$nlog1.06 |
$>$> | $\log3$log3 |

$n$n |
$>$> | $\frac{\log3}{\log1.06}$log3log1.06 |

$n$n |
$>$> | $18.8542$18.8542 |

$\therefore$∴ $n$n |
$=$= | $19$19 |

Thus it will take $19$19 years to triple the principal.

A problem gambler is expected to lose $12$12% of his stake each night he plays the poker machines at his local club. He starts with $$1000$1000 on Monday night, puts the entire amount through the machine, and then leaves with his takings. He uses his takings from the previous night to repeat the pattern on the next night, putting the entire amount through the machine and leaving once again with his takings. Based on his expected losses, when do we expect him to have $10$10% of his original amount left?

**Think:** An expected loss of $12$12% is equivalent to saying that he is expected to leave with $88$88% of his money each night.

So after night $n$`n`, the amount remaining $T$`T` will be given by $T_n=1000\left(1-0.12\right)^n=1000\left(0.88\right)^n$`T``n`=1000(1−0.12)`n`=1000(0.88)`n`.

For example, the amount left after $5$5 nights becomes $T_5=1000\left(0.88\right)^5=527.73$`T`5=1000(0.88)5=527.73.

This is only an expected position, and he may well be slightly worse off or better off than this. We do know with some certainty that, on average, people who gamble in this way will inevitably lose their money.

**Do:** The answer to the specific question asked can be determined by solving $1000\left(0.88\right)^n=0.1\left(1000\right)$1000(0.88)`n`=0.1(1000) as follows:

$1000\left(0.88\right)^n$1000(0.88)n |
$=$= | $0.1\left(1000\right)$0.1(1000) |

$\left(0.88\right)^n$(0.88)n |
$=$= | $0.1$0.1 |

$n\log\left(0.88\right)$nlog(0.88) |
$=$= | $\log\left(0.1\right)$log(0.1) |

$n$n |
$=$= | $\frac{\log\left(0.1\right)}{\log\left(0.88\right)}$log(0.1)log(0.88) |

$n$n |
$\approx$≈ | $18$18 |

Hence, after $18$18 days the gambler expects to have lost $$900$900 of his original stake.

Consider the function $y=0.68\left(1.6\right)^x$`y`=0.68(1.6)`x`.

Identify what type of function this is:

Exponential growth

AExponential decay

BExponential growth

AExponential decay

BWhat is the rate of growth?

Justin purchased a piece of sports memorabilia for $\$2900$$2900, and it is expected to increase in value by $9%$9% per year.

Write a function $y$

`y`to represent the value of the piece of sports memorabilia after $v$`v`years.Find the value of the piece of sports memorabilia after $8$8 years to the nearest cent.

A sample contains $300$300 grams of carbon-11, which has a half-life of $20$20 minutes.

Write a function, $A$

`A`, to represent the amount of carbon-11 remaining in the sample after $t$`t`minutes.Find how much of the isotope would be left after $3$3 hours. Give your answer correct to two decimal places.

Interpret quadratic and exponential expressions that represent a quantity in terms of its context.

Use the properties of exponents to transform expressions for exponential functions.

Create equations in two or more variables to represent relationships between quantities; graph equations on coordinate axes with labels and scales.

Write a function defined by an expression in different but equivalent forms to reveal and explain different properties of the function.

Use the process of factoring and completing the square in a quadratic function to show zeros, extreme values, and symmetry of the graph, and interpret these in terms of a context.

Use the properties of exponents to interpret expressions for exponential functions.

Write a quadratic or exponential function that describes a relationship between two quantities.

Determine an explicit expression, a recursive process, or steps for calculation from a context.