We have now see our four main operations, addition, subtraction, multiplication and division, with different types of rational numbers. What applications or practical problems can we solve using these skills? Before we jump into worded problems, here are reminders of what we have seen so far:
When working with practical problems, it is important to be able to identify keywords. Here is a list of a selection, what other ones can you think of?
Addition: add, both, combined, increase, join, more, plus, sum, together, total
Subtraction: decrease, difference, fewer, left over, less, minus, subtract, take away
Multiplication: by, double, groups of, multiply, of, per, product, times
Division: divide, evenly, half, quotient, shared, split
There are many different strategies we can use to solve practical problems, we will just show one approach, but that doesn't mean there aren't other great ways!
In the morning it was $5$5 $^\circ$°C and it went up $6$6 $^\circ$°C during the day and then went down $13$13 $^\circ$°C in the evening. Write an number sentence for the temperature throughout the day and evaluate it to find the temperature at the end of the day.
Think: We can represent this with integers as they are positive and negatives of whole numbers. Going "up" will be positive and going "down" will be negative.
Do:
$5+6-13$5+6−13 |
Starting at $5$5 and then going up $6$6 and then down $13$13 |
|
$=$= | $11-13$11−13 |
We can work from left to right $5+6=11$5+6=11 |
$=$= | $-2$−2 |
We are subtracting a larger number from a smaller number, so expect a negative |
The temperature at the end of the day was $-2$−2 $^\circ$°C.
Reflect: How could you use a number line to draw out this scenario?
How many $0.26$0.26 L glasses can a $20.8$20.8 L water bottle fill?
Think: We can are splitting the $20.8$20.8 L into a number of $0.26$0.26 L glasses. "Split" is one of our keywords which tells us we need to divide.
Do: Write this as a division problem:
$20.8\div0.26$20.8÷0.26 |
We are dividing the $20.8$20.8 L among the $0.26$0.26 L glasses |
|
$=$= | $2080\div26$2080÷26 |
We can multiply both by $100$100 to eliminate the decimal |
$=$= | $80$80 |
Use long division to evaluate |
$80$80 glasses can be filled.
Reflect: If we were only asked to estimate, what might we estimate? Is our answer reasonable?
A baker has $2$2 cups of flour left. A cake requires $1\frac{1}{5}$115 cups of flour and cookies require $\frac{3}{4}$34 cups of flour. Will the baker have enough flour? How much will they have left or be short? Write a number sentence to justify your answer.
Think: If we start with $2$2 cups and use $1\frac{1}{5}$115 cups and then another $\frac{3}{4}$34 of a cup, we need to subtract $1\frac{1}{5}$115 and $\frac{3}{4}$34 from $2$2.
Do:
$2-1\frac{1}{5}-\frac{3}{4}$2−115−34 |
Taking away the two different amount of flour |
|
$=$= | $2-\frac{6}{5}-\frac{3}{4}$2−65−34 |
Write $1\frac{1}{5}$115 as an improper fraction |
$=$= | $\frac{40}{20}-\frac{24}{20}-\frac{15}{20}$4020−2420−1520 |
Write with a common denominator |
$=$= | $\frac{16}{20}-\frac{15}{20}$1620−1520 |
Subtract from left to right |
$=$= | $\frac{1}{20}$120 |
Subtract from left to right |
We get positive $\frac{1}{20}$120, so the baker will have enough for both the cake and the cookies with $\frac{1}{20}$120 of a cup to spare.
Reflect: How could you solve this problem using another strategy?
Consider the following phrase:
The quotient of $-3$−3 and the sum of $7$7 and $6$6 .
Without simplifying the result, translate this sentence into a mathematical expression.
Evaluate the expression.
Jenny takes out a loan of $\$2200$$2200. She pays back $\$42.60$$42.60 each month and doesn't have to pay interest.
If she has made $5$5 repayments so far, how much does Jenny still owe?