5.03 Distributing to solve
Introduction
Algebra is useful when solving equations because it allows for multiple different methods. Depending on the question and the numbers involved, we can choose which is the most appropriate approach, and hopefully save some time.
One of these methods is distributing to solve, and it can save a lot of work when used appropriately.
Distribute in an equation
Using the distributive law in an equation with algebraic terms follows the same rules that we use to distribute a numeric expression.
The distributive law allows us to expand multiplication applied to an expression inside a pair of brackets according to the rule:A(B+C)=AB+AC
Using the distributive law when solving an equation can help us reduce the equation to only the four basic operations, since we can use it to expand brackets.
By expanding the brackets first, the order in which we apply reverse operations becomes more obvious.
Let's have a look at what happens if we solve the equation 7(r-2)+5=37 using only reverse operations.
If we do this, we get the working out:
| \displaystyle 7(r-2)+5 | \displaystyle = | \displaystyle 37 | |
| \displaystyle 7(r-2) | \displaystyle = | \displaystyle 32 | Reverse the addition |
| \displaystyle r-2 | \displaystyle = | \displaystyle \dfrac{32}{7} | Reverse the multiplication |
| \displaystyle r | \displaystyle = | \displaystyle \dfrac{32}{7}+2 | Reverse the subtraction |
| \displaystyle r | \displaystyle = | \displaystyle \dfrac{32}{7}+\dfrac{14}{7} | Convert 2 to a fraction with denominator 7 |
| \displaystyle r | \displaystyle = | \displaystyle \dfrac{46}{7} | Perform the addition |
We find that it takes more steps to solve the equation using only reverse operations and it involves a lot more fractions.
As such, while both methods for solving the equation work just fine, using the distributive law can save us some time.
The other reason to use the distributive law when solving equations is that there are some problems we simply can't solve using just reverse operations. Consider the equation:3(p-2) + 4(2p+8)=81
Because we can't reverse the multiplications of 3 and 4 at the same time, it's actually impossible to solve this equation using only reverse operations. But we can solve it using the distributive law.
If we use the distributive law to expand all the brackets first, we will only have multiplication, addition and subtraction left. We can then gather any like terms and apply reverse operations, like so:
| \displaystyle 3(p-2) + 4(2p+8) | \displaystyle = | \displaystyle 81 | |
| \displaystyle 3\times p + 3\times2 + 4\times2p + 4\times8 | \displaystyle = | \displaystyle 81 | Use the distributive law |
| \displaystyle 3p-6 + 8p+32 | \displaystyle = | \displaystyle 81 | Simplify the products |
| \displaystyle 11p+26 | \displaystyle = | \displaystyle 81 | Combine like terms |
| \displaystyle 11p | \displaystyle = | \displaystyle 55 | Reverse the addition |
| \displaystyle p | \displaystyle = | \displaystyle 5 | Reverse the multiplication |
Examples
Example 1
Solve this equation for x by first expanding the brackets:-6(4x+5)=-143
Example 2
Solve this equation for x by first expanding the brackets and collecting like terms:4(4x-6)-3x+8=36
Example 3
Solve this equation for x by first expanding the brackets:-3(2x-6) + 5(4x-5)=21
The distributive law allows us to expand multiplication applied to an expression inside a pair of brackets according to the rule:A(B+C)=AB+AC
By expanding the brackets first, the order in which we apply reverse operations becomes more obvious and it can save time in solving the equation.