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6.02 Discriminant

Lesson

Quadratic equations and parabolas

We have seen when solving quadratic equations that there can be two, one or no real solutions. Let's think about the graphs of quadratics:

No solutions One solution Two solutions

 

As shown above there are only three possibilities, with respect to $x$x intercepts, when graphing quadratics. These possibilities are as follows:

  • No real solutions. This means there are no $x$x-intercepts or real zeros.  
  • One real solution. This is where the two zeros are actually equal, and the parabola has one $x$x-intercept where it just touches the $x$x-axis at the turning point.
  • Two real solutions. These are the two distinct zeros or $x$x-intercepts, where the quadratic passes through the $x$x-axis.

The solutions to a quadratic equation correspond to the $x$x values that occur when $y=0$y=0 in a quadratic function, and these are the places where a function crosses the $x$x-axis.

 

The discriminant

We have revised a range of algebraic techniques to solve quadratic equations, and obviously, if we are able to find these actual solutions, we can answer the question of how many solutions or roots a quadratic has. But there is a faster way!

Let's look again at the quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$x=b±b24ac2a

Specifically, let's look at what happens if the square root part $\sqrt{b^2-4ac}$b24ac takes on different values...

$b^2-4ac<0$b24ac<0  or  $b^2-4ac=0$b24ac=0  or  $b^2-4ac>0$b24ac>0 

  • If $b^2-4ac<0$b24ac<0, then the square root is negative, and we know that we cannot take the square root of a negative number and get real solutions. This is the case where we have zero real roots.
  • If $b^2-4ac=0$b24ac=0, then the square root is $0$0 and then the quadratic equation becomes just $x=\frac{-b}{2a}$x=b2a. and we have a single root. This is actually the equation for the axis of symmetry.
  • If $b^2-4ac>0$b24ac>0, then the square root will have two values, one for $+\sqrt{b^2-4ac}$+b24ac and one for $-\sqrt{b^2-4ac}$b24ac. The quadratic formula will then generate for us two distinct real roots. If this value is a square number, we will have two rational roots, seeing as the square root of a square number will lead us with a rational result. For any other positive number, we will end up with two roots with surds in them. 

This expression $b^2-4ac$b24ac within the quadratic formula is called the discriminant, and it determines the number of real solutions a quadratic function will have. The symbol $\Delta$Δ is used as a shortcut for$b^2-4ac$b24ac .

 

Discriminant of a quadratic $\Delta$Δ

$b^2-4ac<0$b24ac<0, $0$0 real solutions, $2$2 complex roots, the parabola has no $x$x-intercepts

$b^2-4ac=0$b24ac=0, $1$1 real solution, $2$2 equal real roots, the parabola just touches the $x$x-axis 

$b^2-4ac>0$b24ac>0, $2$2 real solutions, $2$2 distinct real roots, the parabola passes through two different points on the $x$x-axis that may be rational or irrational

 

Remember that every quadratic function can be sketched, even if it has no real roots. Every quadratic function is a parabola and has a vertex, which means that it has either a maximum or minimum value which can be found. Knowing the value of the discriminant, and the value of $a$a in $y=ax^2+bx+c$y=ax2+bx+c which determines its concavity, can give us enough information for a rough sketch of the parabola.

Use the following applet to explore how the discriminant relates to the number of solutions to a quadratic equation.

 

Practice questions

Question 1

Consider the equation $4x^2-6x+7=0$4x26x+7=0.

  1. Find the value of the discriminant.

  2. Using your answer from the previous part, determine the number of real solutions the equation has.

    2

    A

    0

    B

    1

    C

Question 2

Consider the equation $x^2+22x+121=0$x2+22x+121=0.

  1. Find the value of the discriminant.

  2. Using your answer from the previous part, determine whether the solutions to the equation are rational or irrational.

    Irrational

    A

    Rational

    B

Question 3

Consider the equation $x^2+18x+k+7=0$x2+18x+k+7=0.

  1. Find the values of $k$k for which the equation has no real solutions.

  2. If the equation has no real solutions, what is the smallest integer value that $k$k can have?

Question 4

Identify the graph of the quadratic $f\left(x\right)=ax^2+bx+c$f(x)=ax2+bx+c, where $a>0$a>0 and $b^2-4ac=0$b24ac=0.

  1. Loading Graph...

    A

    Loading Graph...

    B

    Loading Graph...

    C

    Loading Graph...

    D

Outcomes

MA11-1

uses algebraic and graphical techniques to solve, and where appropriate, compare alternative solutions to problems

MA11-2

uses the concepts of functions and relations to model, analyse and solve practical problems

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